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scoundrel [369]
3 years ago
11

74%of 238express the part as a whole number

Mathematics
1 answer:
Mashutka [201]3 years ago
5 0
74% x 238 = 176.12 Answer is 176 if rounded.
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During a musical an orchestra is playing. As the music plays, the volume changes in the beginning of the piece can be modeled by
noname [10]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the model:

s = 10│x - 4│+ 50

s represents the sound level in decibels and x represents the number of measures of music played

To find x at s = 80

The equation becomes /

80 = 10│x - 4│+ 50

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80 - 50 = 10 |x - 4| + 50 - 50

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3 years ago
(4.70x10^3)+(8.6x10^5)
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Answer:

8.647 x 10^5

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3 years ago
The graph of y = x^2 has been translated 7 units to the left. The equation of the resulting parabola is _____.
Marina86 [1]
Move c  units to left means add c to every x

move 7 so add 7 to every x

y=(x+7)^2


2nd option iis answer
3 0
3 years ago
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If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
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