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bixtya [17]
3 years ago
8

I think of a number times it by 5 then take away from 17

Mathematics
1 answer:
polet [3.4K]3 years ago
3 0

Answer:

YOUR WELCOME

Step-by-step explanation:

 

To work out the number you started with, all you have to do is reverse the instructions that it gives you.  

Jack, also from Wilson's School, explained further...

there is a simple calculation that is done when you enter in your result.

The machine reverses the order in which things are done.

You add 4,

then you double the result,

then you subtract 7

and you get the answer.

When you type that in and it says that it is "processing data" what it is actually doing is the calculation

 

Add 7

then divide by 2

then subtract 4

 

Andreas, also from Wilson's, worked through an example:

If the last number was 39, what you would do is:

39 + 7 which equals 46.

Then you divide by two, giving 23.

Finally you subtract 4 and get 19.

So 19 was the starting number.

What you are doing is reversing the operations done, to get the original number.

An equation would be: A= ([y+7] ÷2) -4

 

David from Comberton Village College noticed that there is a quicker alternative:

 

Imagine your number was x.

So when you think of a number, you effectively think:

x

Next you add 4: x+4

Then you double it: 2(x+4) = 2x+8

Then you subtract 7: 2x+1

All the machine has to do now is

Subtract 1: 2x

And then halve the result: x

This gives you the starting number.  

 

Charlotte & Thom from Twyford C of E High School described both methods:

 

The machine can work out the number someone started with, in a few different ways.

Firstly the machine can do the inverse operation:

If you end up with the answer 13 you can work out the starting number like so:

13 + 7 = 20

20 ÷ 2 = 10

10 - 4 = 6

So that means the number you started with must have been 6.

We can check this by following the original set of instructions and using the number 6 for the calculations like so:

6 + 4 = 10

10 x 2 = 20

20 - 7 = 13

We now know that this theory is correct.

However the machine could use a different way.

When you test out different numbers you start to see a pattern emerging:

If you start with the number 6 you get the answer 13

If you start with the number -2.5 you get then answer -4

If you start with the number 71 you will get the answer 143

If you start with the number 0.12 you will get the answer 1.24

When you start to look at the relationships between the first number and the answer, you can make an equation:

if the first number you think of is n,

and the answer is y,

the equation to work out the answer would be: y = 2n + 1

This means that the answer you get is two times the number you started with, plus 1.

Therefore the machine can work out your staring number once again by doing the inverse operations in reverse order, so it subtracts 1 from the number you got and then divides it by 2.

Megan, also from Twyford C of E High School, reached the solution by working algebraically:

 

x = the number you thought of

x + 4

2 (x + 4)

2 (x + 4) -7  

equals the number you finished with, which we are going to call y

2 (x + 4) - 7 = y

2x + 8 - 7 = y

2x + 1 = y

2x = y - 1

x = y−12

To find the number you thought of, you take away 1 from the number you finished with and then divide by 2.

Niteesh from Vidya Shilp Academy in Bangalore created a similar puzzle:

All the machine needs to do to get the original number is undo the procedure.

The machine first adds 7, then halves the answer and then subtracts 4 to get the original number.

If I were to make a similar machine the rules would be:

Think of a number

Double it

Add 2

Halve the answer

Enter the result

So the machine would have to take the result and

Double it

Subtract 2

Halve the answer.

And the result would be the user's original number.

 

Well done to you all.

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vlada-n [284]

Answer:

  A.) the SSS Postulate

Step-by-step explanation:

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4 0
2 years ago
Compute and compare the side lengths of the two figures. Does this support an argument claiming that they are congruent? What el
Sunny_sXe [5.5K]
We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].

AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13

BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13

CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13

DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13

The two polygons are squares with the same side lengths. 

But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions: 
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2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.

The third condition was not proven.
6 0
3 years ago
Read 2 more answers
the seats at a local baseball stadium are arranged so that each row has 5 more seats than the row below it. if there are 4 seats
Dvinal [7]
The given in the problem above is an arithmetic sequence with the first term equal to 4 and the common difference is 5. To determine the number of seats on row 23, use the formula,                                          an = a1 + (n - 1) d
Solving for the 23rd term,                                            an  = 4 + (22) 5 = 114 seats
Therefore, the answer is there are 114 seats on the 23rd row. 
 Welcome Bby (;
6 0
3 years ago
Can someone help me with at least one problem and tell me how you got the answer
Vesna [10]
S=16t^2
if t=3 
So you would plug it in
16(3)^2 
Then you multipy 
16*3^2
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It is easier if you use a calculator just type in ti 30 calculator online that should help

4 0
3 years ago
PLEASE I NEED HELP ASAP
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1. 15x
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You’re welcome
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2 years ago
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