Is 6(5x-3) equivalent to 8-2(5x-3)
1 answer:
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Answer:
D. I and III only
Step-by-step explanation:
Number of first fie defects are given as 9,7,10,4 and 6.
First we have to arrange the above data in ascending order which is 4,6,7,9,10
- Now if we consider the defect in sixth car to be 3 then our data will look like: 3,4,6,7,9,10
So the mean of above data would be = 6.5
and Median of the above data would be = =
= 6.5
Hence mean and median number of defects are same if the sixth car has 3 defects.
- Now if we consider the defect in sixth car to be 12 then our data will look like: 4,6,7,9,10,12
So the mean of above data would be = 8
and Median of the above data would be = =
= 8
Hence mean and median number of defects are same if the sixth car has 12 defects.
- But Now if we consider the defect in sixth car to be 7 then our data will look like: 4,6,7,7,9,10
So the mean of above data would be = 7.167
and Median of the above data would be = = 7
Hence mean and median number of defects are not same if the sixth car has 7 defects.
Therefore option D is correct.
Answer:
- not linear
- somewhere between 184 and 186 (maybe)
Step-by-step explanation:
As you show, the weight differences are different for the same week differences, so the table is not linear. A graph (attached) can also show you the table is not linear.
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The highest rate of weight loss shown in the table is 7 lbs in 3 weeks, or 4 2/3 pounds in 2 weeks. The lowest rate of weight loss shown in the table is 5 lbs in 3 weeks, or 3 1/3 pounds in 2 weeks. Based on the rates shown in the table, we might expect the starting weight to be between 3 1/3 and 4 2/3 pounds more than the first table value:
Week 0 weight: between 184 1/3 and 185 2/3 lbs, estimated.
_____
A "line of best fit" for the data has a y-intercept of about 185 pounds, which is the midpoint between our two estimates above.
