k = 13The smallest zero or root is x = -10
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Steps:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+1 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
Please mark brainliest
<em><u>Hope this helps.</u></em>
Answer:
- a) 11, d) 25, e) 14, b) 25, c) 28, f) 33
Step-by-step explanation:
<h3>Given</h3>
- ΔBDF, with H is the centroid of BDF, DF = 50, CF = 42, and BH = 22
<h3>To find</h3>
<h3>Solution</h3>
As per definition of the centroid, the points C, E and G are midpoints of respective sides and the length of short and long distances from the centroid have ratio of 1/3 and 2/3 of median
- a) HE = 1/2BH = 1/2(22) = 11
- d) DE = 1/2DF = 1/2(50) = 25
- e) CH = 1/3CF = 1/3(42) = 14
- b) EF = DE = 25
- c) HF = 2/3CF = 2/3(42) = 28
- f) BE =BH + HE = 22 + 11 = 33
1. The weights of 30 students in a class ( in Kg ) are as follows. 42 , 52, 46 ,63, 47 ,40,50,63,52, 57,40,47,55 ,52, 49, 42,56,
enyata [817]
Step-by-step explanation:
I think when you put the numbers orderwise
The range 40 - 50 in which most students lie
