Current amount in account
P=36948.61
Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n
Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11
We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000
We can solve this by trial and error.
The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000. It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.
So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.
So it takes 15.00 years to reach the goal of 280000 years.
Answer:
<em>T </em><em>=</em><em> </em><em>1</em><em>6</em>
Step-by-step explanation:
As triangles are similar
AB/DE = BC/EF = AC/DF
13.5/18 = 6/4 = 12/T
3/4 = 3/4 = 12/T
3/4 = 12/T
T = 12×4/3
T = 16
Answer:
Step-by-step explanation:
0.9*2b = 1.8b
0.9*-1 = -0.9
So far we have 1.8b-0.9. It can't be simplified further.
Then, we add the 2nd part, -0.5b+1.
We have:
1.8b-0.9-0.5b+1. Next we combine like terms.
1.8b-0.5b = 1.3b.
-0.9+1 = 0.1
Then we put it together.
1.3b+0.1 is our answer.
Hope this helped! Have a nice day :D
X² - 6x +9
x -3
x -3
D) (x - 3) (x -3) is your answer
To check, do your FOIL
x(x) = x^2
x(-3) = -3x
-3(x) = -3x
-3(-3) = 9
x^2 -6x +9 True
hope this helps
- 9/ ((-x^2 + 9)^1/2(x+ 3))(x-3)
