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oksian1 [2.3K]
2 years ago
13

4^3/2 Rewrite in radical form and then simplify

Mathematics
2 answers:
Dafna11 [192]2 years ago
6 0

Answer:

8

Step-by-step explanation:

27^\frac{1}{3} is the same as \sqrt[3]{27^1}. To write an exponent in radical form , the denominator, or index goes in front of the radical, and the numerator goes inside of the radical. We raise the base to the power of the numerator.

4^{ \frac{3}{2}} is the same as \sqrt4^3}

\sqrt{64}

\sqrt(8*8)

\cancel\sqrt(8^\cancel2) (cancel)

= 8

german2 years ago
4 0

Answer:

8

Step-by-step explanation:

radical form conversion uses the equation: \alpha ^\frac{z}{n} =  `^n\sqrt{a^x}

Use the rule to convert 4^3/2 to a radical, where a = 4,  x = 3, and n = 2

\sqrt{4^3}

simplified, your answer is 8

hope this helps:)

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Help me please I need this in by tomorrow
galina1969 [7]

Answer:

BDA=29°, BCD=72°

4 0
4 years ago
Suppose that in the inventory problem, the storage cost depends on the maximum inventory size, rather than the average. This wou
aniked [119]

Answer:

Suppose that in the inventory problem, the storage cost depends on the maximum inventory size, rather than the average. This would be more realistic if, for example, the company had to build a warehouse large enough to hold the maxi- mum inventory, and the cost of storage was the same no matter how full or empty the warehouse was. Show that in this case the number of units that should be ordered or manufactured to minimize the total cost is q= âfM/k

Step-by-step explanation:

Suppose that in the inventory problem, the storage cost depends on the maximum inventory size, rather than the average. This would be more realistic if, for example, the company had to build a warehouse large enough to hold the maxi- mum inventory, and the cost of storage was the same no matter how full or empty the warehouse was. Show that in this case the number of units that should be ordered or manufactured to minimize the total cost is q= âfM/k

5 0
3 years ago
in the life of a car engine, calculatedin miles, is normally distributed, with a mean of 17,000 miels and a standard deviation o
Alinara [238K]

Answer:

the guarantee period should be less than 136010 miles

Step-by-step explanation:

From the given information;

Let consider Y to be the life of a car engine

with a mean μ = 170000

and a standard deviation σ = 16500

The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.

i.e

P(Y < T ) < 0.02

For the variable of z ; we have:

z = \dfrac{x - \mu }{\sigma}

z = \dfrac{x - 170000 }{16500}

Now;

P(Y < T ) = P( Z < \dfrac{T- 170000}{16500})

P( Z < \dfrac{T- 170000}{16500})< 0.02

From Z table ;

At P(Z < -2.06) ≅ 0.0197  which is close to 0.02

\dfrac{T- 170000}{16500}

{T- 170000}

{T- 170000}< - 33990

{T}< - 33990+ 170000

{T}

Thus; the guarantee period should be less than 136010 miles

4 0
4 years ago
What is the point-slope form of an equation with the slope of 3/5 that passes through the point (10, –2)?
bekas [8.4K]
Answer to the first question is A. X = 10 and y = -2. Plug it into the equation.
-2 + 2 = 3/5(10 - 10)
0 = 0

Answer to the second question is A. It is going up "rise" by 4. And left "run" by -5

Answer to the third question is A. 2x will represent the slope. 5 will represent the y intercept.

Answer to the fourth question is C.

Answer to the last question is B. y = 5(1) y = 5. y = 5(0) y = 0.

Hope that helps
8 0
4 years ago
LOOK AT THEBLINE PLOT: 0, 1/4, 1/2, 3/4, 1
Sloan [31]
First add them all up.
0+1/4+1/2+3/4+1=2.5
Because there are 5 beakers you divide 2.5 or 2 1/2 by 5 and you get .5 or 1/2
there would be 1/2 water in each beaker.
7 0
3 years ago
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