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solmaris [256]
3 years ago
15

Dividing a two number always leav a remainder?

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

i dont know i wanna ask too

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Doug's printing business had a revenue of $6,000 and operating costs of $4,000. How much profit did his business make?
ryzh [129]
$2,000 because operating costs means how much money he needs to keep the business going and revenue is how much he makes
4 0
3 years ago
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Find the value of x that makes def ~ xyz<br>x=​
Neporo4naja [7]

Answer:

x = 3.5

Step-by-step explanation:

\triangle DEF \sim \triangle XYZ\\\\\therefore \frac{DE}{XY} =\frac{DF}{XZ} \\\\\therefore \frac{5}{7.5} =\frac{7}{3x} \\\\\therefore 3x = \frac{7.5\times 7}{5} \\\\\therefore x = \frac{7.5\times 7}{3\times 5} \\\\\therefore x = \frac{52.5\times 7}{15} \\\\\therefore x = 3.5

6 0
3 years ago
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PLZZZ HELP ME GIVING 20 POINTTSSSS
melisa1 [442]

Answer:4/5

Step-by-step explanation:

I think it's 4/5 because the number 3 is only one number of 5. And if you subtract 5-1, you'll get 4.

8 0
3 years ago
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PLSSSSS HELLLLLLP!!!!!
Lapatulllka [165]

Answer:

\frac{3n^2-7n+15}{(n+3)(n-4)} will be the answer.

Step-by-step explanation:

The given expression is,

\frac{3n}{(n+3)}+\frac{5}{(n-4)}

By solving this expression,

\frac{3n}{(n+3)}+\frac{5}{(n-4)}

= \frac{3n(n-4)}{(n+3)(n-4)}+\frac{5(n+3)}{(n+3)(n-4)}

= \frac{3n(n-4)+5(n+3)}{(n+3)(n-4)}

= \frac{3n^2-12n+5n+15}{(n+3)(n-4)}

= \frac{3n^2-7n+15}{(n+3)(n-4)}

Therefore, fraction given in option (2) will be the answer.

4 0
3 years ago
Which is the best description for the graph below?<br><br> A graph decreases from (0, 3) to (9, 0).
AURORKA [14]

Answer:

Step-by-step explanation:

As we move from (0, 3) to (9, 0), we see x increasing by 9.  This is the 'run.'

At the same time, we see y decreasing by 3.  This is the 'rise.'

The slope of this line (graph) is m = rise / run = -3/9, or m = -1/3

Since we witness a decrease in y as we move from the first point to the second, we immediately suspect that the slope is negative.

8 0
3 years ago
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