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4 years ago

Which is equivalent to 5 and 2 fifthteenthes

Mathematics

2 answers:

Rom4ik [11]4 years ago

7 0

Answer:

Step-by-step explanation:

5 2/15= 77/15

nikklg [1K]4 years ago

6 0

Answer:

32/15 = 5 2/15

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Carlos rented a truck for one day. There was a base fee of $19.99, and there was an additional charge of 86 cents for each mile

NeX [460]

Answer: 211 miles

Step-by-step explanation: An equation for this could be:

base fee + additional charge (miles driven) = total charge

19.99 + 0.86(x) = 201.45

0.86(x) = 201.45 - 19.99

0.86(x) = 181.46

x = $\frac{181.46}{0.86}$ = 211 miles

6 0

2 years ago

I don't know the math steps to this math problem, (9-5) 2 squared

astraxan [27]

Answer:

16 is the answer

Step-by-step explanation:

(9-5)²
(4)²
4×4
16

3 0

3 years ago

Read 2 more answers

You want to make 3 pairs of earrings that are in the shape of isosceles triangles. Each earring will have a base of 2 cm. The wi

son4ous [18]

Answer:

The length of each of the other two sides would be 3.1 cm

Step-by-step explanation:

The options of the question are

A. 3.1 cm

B. 3.2 cm

C. 4.2 cm

D. 6.1 cm

we know that

An isosceles triangle has two equal sides and two equal interior angles

Let

x -----> the length of each of the two equal sides in the isosceles triangle

The perimeter of one isosceles triangle is equal to

$P=2x+2$

Remember that

To maximize the use of the wire, the perimeter of 6 earrings (3 pairs of earrings) must be equal to 50 cm

$6(2x+2)=50$

Solve for x

$12x+12=50$

$12x=50-12$

$12x=38$

$x=\frac{38}{12}=3.16\ cm$

therefore

The length of each of the other two sides would be 3.1 cm

7 0

3 years ago

How do I do that it's systems of equations

Tpy6a [65]

You have to get y alone,

6 0

4 years ago

The angle \theta_1θ

enyata [817]

Answer:

$sin\theta_1 = \dfrac{\sqrt{217}}{19}$

Step-by-step explanation:

It is given that:

$cos\theta_1 = -\dfrac{12}{19}$

And we have to find the value of $sin\theta_1 = ?$

As per trigonometric identities, the relation between $sin\theta\ and \ cos\theta$ can represented as:

$sin^2\theta + cos^2\theta = 1$

Putting $\theta_1$ in place of $\theta$ Because we are given

$sin^2\theta_1 + cos^2\theta_1 = 1$

Putting value of cosine:

$cos\theta_1 = -\dfrac{12}{19}$

$sin^2\theta_1 + (\dfrac{12}{19})^2 = 1\\\Rightarrow sin^2\theta_1 + \dfrac{144}{361} = 1\\\Rightarrow sin^2\theta_1 = 1-\dfrac{144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{217}{361}\\\Rightarrow sin\theta_1 = +\sqrt{\dfrac{217}{361}}, -\sqrt{\dfrac{217}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{\sqrt{217}}{19}, -\dfrac{\sqrt{217}}{19}$

It is given that $\theta_1$ is in 2nd quadrant and value of sine is always positive in 2nd quadrant. So, the answer is.

$\Rightarrow sin\theta_1 = \dfrac{\sqrt{217}}{19}$

8 0

3 years ago