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Agata [3.3K]
4 years ago
13

Which is equivalent to 5 and 2 fifthteenthes

Mathematics
2 answers:
Rom4ik [11]4 years ago
7 0

Answer:

Step-by-step explanation:

5 2/15= 77/15

nikklg [1K]4 years ago
6 0

Answer:

32/15 = 5 2/15

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Carlos rented a truck for one day. There was a base fee of $19.99, and there was an additional charge of 86 cents for each mile
NeX [460]

Answer: 211 miles

Step-by-step explanation: An equation for this could be:

base fee + additional charge (miles driven) = total charge

19.99 + 0.86(x) = 201.45

0.86(x) = 201.45 - 19.99

0.86(x) = 181.46

x = \frac{181.46}{0.86} = <em>211 miles</em>

6 0
2 years ago
I don't know the math steps to this math problem, (9-5) 2 squared
astraxan [27]

Answer:

16 is the answer

Step-by-step explanation:

  • (9-5)²
  • (4)²
  • 4×4
  • 16
3 0
3 years ago
Read 2 more answers
You want to make 3 pairs of earrings that are in the shape of isosceles triangles. Each earring will have a base of 2 cm. The wi
son4ous [18]

Answer:

The length of each of the other two sides would be  3.1 cm

Step-by-step explanation:

<u><em>The options of the question are</em></u>

A. 3.1 cm

B. 3.2 cm

C. 4.2 cm

D. 6.1 cm

we know that

An isosceles triangle has two equal sides and two equal interior angles

Let

x -----> the length of each of the two equal sides in the isosceles triangle

The perimeter of one isosceles triangle is equal to

P=2x+2

Remember that

To maximize the use of the wire, the perimeter of 6 earrings (3 pairs of earrings) must be equal to 50 cm

so

6(2x+2)=50

Solve for x

12x+12=50

12x=50-12

12x=38

x=\frac{38}{12}=3.16\ cm

therefore

The length of each of the other two sides would be  3.1 cm

7 0
3 years ago
How do I do that it's systems of equations
Tpy6a [65]
You have to get y alone, 

6 0
4 years ago
The angle \theta_1θ
enyata [817]

Answer:

sin\theta_1 = \dfrac{\sqrt{217}}{19}

Step-by-step explanation:

It is given that:

cos\theta_1 = -\dfrac{12}{19}

And we have to find the value of sin\theta_1 = ?

As per trigonometric identities, the relation between sin\theta\ and \ cos\theta can represented as:

sin^2\theta + cos^2\theta = 1

Putting \theta_1 in place of \theta Because we are given

sin^2\theta_1 + cos^2\theta_1 = 1

Putting value of cosine:

cos\theta_1 = -\dfrac{12}{19}

sin^2\theta_1 + (\dfrac{12}{19})^2 = 1\\\Rightarrow sin^2\theta_1 + \dfrac{144}{361} = 1\\\Rightarrow sin^2\theta_1 = 1-\dfrac{144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{217}{361}\\\Rightarrow sin\theta_1 = +\sqrt{\dfrac{217}{361}}, -\sqrt{\dfrac{217}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{\sqrt{217}}{19}, -\dfrac{\sqrt{217}}{19}

It is given that \theta_1 is in 2nd quadrant and value of sine is always positive in 2nd quadrant. So, the answer is.

\Rightarrow sin\theta_1 = \dfrac{\sqrt{217}}{19}

8 0
3 years ago
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