For this case we have an equation of the form:
h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
Where,
vo: initial speed
a: acceleration:
h0: initial height.
We have the following equation:
h (t) = - 16t2 + 19t + 110
Therefore, the initial velocity is:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown:
vo = 19 feet / s
Solve for p by simplifying both sides of the equation, then isolation the variable
p = 1 + m/2
Hope this helps! :)
You just multiple my guy. 2:3 is like 2/3. What is 2/3 of 39
39*2/3 = 26
4x-7=7x-61
-7=3x-61
54=3x
Answer
X=18
She would've put 11 dimes in each pile. 55/5=11
