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kow [346]
3 years ago
13

#15. Write the equation of each circle.

Mathematics
1 answer:
frosja888 [35]3 years ago
5 0

Answer:

Step-by-step explanation:

The center is at (1,-2) from the graph.

The radius is 2 [3 - 1 on the horizontal]

The equation of the circle is

(x - 1)^2 + (y + 2)^2 = 2^2

(x - 1)^2 + (y + 2)^2 = 4

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Part A Mr. Bade spends an average of $42.50 during a five-day workweek on lunch.if he eats every day during his 5-day workweek,
trasher [3.6K]

Answer:

Part A: He spends an average of $8.50 per day

Part B:  He would save $17 per week

Step-by-step explanation:

4 0
3 years ago
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What is the sum of StartRoot negative 2 EndRoot and StartRoot negative 18 EndRoot?
Darya [45]

Answer:

4 \sqrt{2} i

Step-by-step explanation:

We want to find the sum of

\sqrt{ - 2}  +  \sqrt{ - 18}

We can rewrite this as

\sqrt{ 2 \times  - 1}  +  \sqrt{ 18 \times  - 1}

This becomes;

\sqrt{2}  \times  \sqrt{ - 1}  +  \sqrt{18}  \times  \sqrt{ - 1}

Recall that;

i =  \sqrt{ - 1}

This implies that;

\sqrt{2} i + 3 \sqrt{2} i

Combine like terms:

4 \sqrt{2} i

3 0
3 years ago
Need help finding a constant k at which the function is continuous everywhere.
saveliy_v [14]

Answer:

k = -6/35

Step-by-step explanation:

To make the function continuous

kx^2 = x+k

These must be equal where the function is defined for two different intervals

This is at the point x=-6  so let x=-6

k(-6)^2 = -6+k

36k = -6+k

Subtract k from each side

36k-k = -6+k-k

35k = -6

Divide by 35

35k/35 = -6/35

k = -6/35


3 0
3 years ago
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Question 2 (Essay Worth 10 points)
icang [17]

Answer:

Part A: 1 solution

Part B:

3(2x-7)=3

6x-21=3

 +21  +21

6x=24

/6    /6

x=4

Step-by-step explanation:

First you <u>distribute 3(2x-7)=3</u> to 6x-21=3. Next you do inverse operations by <u>adding 21 to both sides</u> of the equation to get 6x=24. Finally you <u>divide both sides by 6</u> to get x=4

7 0
3 years ago
Which of the following expressions are equivalent to 58 ?
Westkost [7]

Answer:

(5^4)^2

Step-by-step explanation:

3 0
2 years ago
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