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1 answer:
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9514 1404 393
Answer:
∠KXN and ∠QXT
Step-by-step explanation:
The measure of each angle is the difference of the scale values that the rays intercept. (The same scale needs to be used for each ray.) Of course, complementary angles have a sum of 90°.
Here, we'll refer to angle aXb as "ab".
NP = 95 -35 = 60
PQ = 35 -20 = 15 . . . not complementary to NP
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KN = 165 -95 = 70
QT = 20 -0 = 20 . . . complementary to KN ⇒ your answer
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JK = 180 -165 = 15
PQ = 35 -20 = 15 . . . not complementary to JK
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JK = 15
NK = KN = 70 . . . not complementary to JK
The correct question statement is:
A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in
. Find 
.
Solution:
Part 1:
means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.
So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:
Thus the set compliment of E will contain the elements {4,5,6}.So
= {4,5,6}
Part 2)
means probability that if we select any number from the Sample Space S, it will belong the set E compliment.
= (Number of Elements in 
)/Number of elements in S
Number of elements in set S = n(S) = 12
Number of elements in set = 
=3
So,
A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in
Solution:
Part 1:
So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:
Thus the set compliment of E will contain the elements {4,5,6}.So
Part 2)
Number of elements in set S = n(S) = 12
Number of elements in set
So,