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monitta
3 years ago
12

Answer Yes or No and explain why in one sentence.(click the picture)

Mathematics
2 answers:
Lilit [14]3 years ago
8 0
Yes, because there are common factors in the equation. therefore showing you can group
ycow [4]3 years ago
3 0
To add or subtract with exponents, the variables and the exponents of the variables must be the same, therefore you cannot group them. However, if you were multiplying the numbers, you'd be able to group them.
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Which expression is equivalent to (84+16)
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Answer:

(85 + 15) is equivalent

Step-by-step explanation:

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Please help me on this , will give brainliest , tyy
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7

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Step-by-step explanation:

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3 years ago
Kenji is traveling in Europe and renting a car. He is used to thinking of gasoline amounts in gallons, but in Europe it is sold
finlep [7]
10.3 gallons

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3 years ago
A group of friends are at a baseball game and are purchasing souvenirs. Dustin purchased 5 t-shirts and 1 baseball cap, spending
Inessa [10]

Answer:

Shirt-$19

Cap-$24

Step-by-step explanation:

5s+1c=119

1s+1c=43

1c=43-1s

substitute:

5s+(43-1s)=119

5s+43-1s=119

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7 0
3 years ago
A manufactured lot of buggy whips has 20 items, of which 5 are defective. A random sample of 5 items is chosen to be inspected.
dimulka [17.4K]

Answer:

a. 39.55%

b. 44.02%

Step-by-step explanation:

We have the following data:

n = 5

x = 1

p = 5/20 = 0.25

to. If the sampling is done with replacement.

We apply the binomial distribution formula, which is as follows:

P = nCx * (p ^ x) * ((1-p) ^ (n-x))

Where nCx, is a combination, and is equal to:

nCx = n! / x! * (n-x)!

replacing we have:

5C1 = 5! / 1! * 4! = 5

replacing in the main formula:

P = 5 * (0.25 ^ 1) * ((1- 0.25) ^ (5-1))

P = 0.3955

that is, without replacing the probability is 39.55%

b. if the sampling is done without replacement.

Here it is a little different from the previous one, but what you should do is calculate three cases,

the first was the one at point a, when n = 5 and x = 1

5C1 = 5! / 1! * 4! = 5

the second is when n = 20 and x = 5, this is all possible scenarios.

20C5 = 20! / 5! * 15! = 15504

and the third is when n = 15 (20-5) and x = 4 (5-1), which corresponds to the cases when none were damaged

15C4 = 15! / 4! * 11! = 1365

In the end, it would be:

P = (5C1 * 15C4) / 20C5

Replacing:

P = 5 * 1365/15504

P = 0.4402

Which means that without replacing the probability is 44.02%

7 0
3 years ago
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