Answer / Step-by-step explanation:
It should be noted that the question is incomplete due to the fact that the diagram has not been provided. However, the diagram has been complementing the question has been provided below.
To solve the question in the narrative, we recall the equation used in solving for displacement:
Thus, δₙₐ = Σ pL/AE
Where:
P is applied axial force.
E is the young's modulus of elasticity.
A is the area of cross-section.
L is length of the bar
Therefore, -8 (80) ÷ π/4 ( 0.85)² (18) (10³) + 2(150) ÷ π/4 (1.1)² (18) (10³) + 6(100) ÷ π/4 (0.45)² (18) (10³)
Solving further,
we have,
-8 (80) ÷ 0.7853( 0.85)² (18) (10³) + 2(150) ÷ 0.7853(1.1)² (18) (10³) + 6(100) ÷ 0.7853 (0.45)² (18) (10³)
= -640÷ 0.7853( 0.85)² (18) (10³) + 300 ÷ 0.7853(1.1)² (18) (10³) + 600 ÷ 0.7853 (0.45)² (18) (10³)
Solving further, we arrive at 0.111 in answer.
The positive sign indicates that end A moves away from end D.
Area of a square = Side x Side (length x width)
A = 1.69 m²
Length = √area of square
L = √1.69 m²
L = 1.3 m
Check Work: 1.3² = 1.3 m x 1.3m
= 1.69 m²
Answer:
10.7 feet
Step-by-step explanation:
The ladder, the ground and the wall form the shape of a right angled triangle as shown in the image below.
The hypotenuse of the triangle is 14 feet (length of ladder)
The base of the triangle is 9 feet long (the distance from the base of the ladder to the wall)
We need to find the height of the triangle. We can apply Pythagoras rule:
![hyp^2 = a^2 + b^2](https://tex.z-dn.net/?f=hyp%5E2%20%3D%20a%5E2%20%2B%20b%5E2)
where hyp = hypotenuse
a = base of the triangle
b = height of the triangle
Therefore:
![14^2 = 9^2 + b^2\\\\196 = 81 + b^2\\\\b^2 = 196 - 81 = 115\\\\b = \sqrt{115} \\\\b = 10.7 feet](https://tex.z-dn.net/?f=14%5E2%20%3D%209%5E2%20%2B%20b%5E2%5C%5C%5C%5C196%20%3D%2081%20%2B%20b%5E2%5C%5C%5C%5Cb%5E2%20%3D%20196%20-%2081%20%3D%20115%5C%5C%5C%5Cb%20%3D%20%5Csqrt%7B115%7D%20%5C%5C%5C%5Cb%20%3D%2010.7%20feet)
The wall reaches 10.7 feet high.
Answer:
d=sqrt(18^2+24^2)=30
Step-by-step explanation: