In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.
In the second case we'd also subtract 1 from both sides, and would obtain
|x-1|>14.
What would the graphs look like?
In the first case, the graph would be on the x-axis with "center" at x=1. From this center count 14 units to the right, and then place a circle around that location (which would be at x=15). Next, count 14 units to the left of this center, and place a circle around that location (which would be -13). Draw a line segment connecting the two circles. Notice that all of the solutions are between -13 and +15, not including these endpoints.
In the second case, x has to be greater than 15 or less than -13. Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right. None of the values in between are solutions.
The answer is D.
Hope it helps!
The complement is what adds to an angle to get 90 degrees
so
x is 25 mroe than 4 times y
x+y=90
x=25+4y
sub 25+4y for x
25+4y+y=90
25+5y=90
minus 25 both sides
5y=65
divide both sides by 5
y=13
sub back
x+y=80
x+13=90
x=77 degrees
Answer:
a=50
Step-by-step explanation:
10/27=a/135
a/135=10/27
a=10/27*135
a=10*45/9
a=10*5
a=50
