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Temka [501]
3 years ago
11

14(1−23)2+13 Enter your answer, as a simplified fraction, in the box.

Mathematics
2 answers:
zmey [24]3 years ago
8 0

Answer:

correct answer is 13/36

Step-by-step explanation:

I took the quiz and got it right

kondor19780726 [428]3 years ago
5 0
-603 is the answer I believe ;') hope this helps!
You might be interested in
8. Solve using any method.<br> 3y – 3 = 3x<br> -3x + 3y = -57
Ksivusya [100]

Answer:

No Solutions.

Step-by-step explanation:

I will solve your system by substitution.

3y−3=3x; −3x+3y=−57

Step: Solve 3y−3=3x for y:

3y−3+3=3x+3 (Add 3 to both sides)

3y=3x+3

(3y/3=3x+3)/3

(Divide both sides by 3)

y=x+1

Step: Substitute x+1 for y in −3x+3y=−57:

−3x+3y=−57

−3x+3(x+1)=−57

3=−57 (Simplify both sides of the equation)

3+(−3)=−57+(−3) (Add -3 to both sides)

0=−60

5 0
3 years ago
What is the quotient of 4 divided by 9/10
kozerog [31]
The answer is 49/9 because you can first convert the fraction into a decimal and devide 4 and 0.9 and you will get 5.4 repeating and which is 49/9
3 0
3 years ago
Read 2 more answers
Kristen reads 11 pages per hour. In all, how many hours of reading will Kristen have to do
soldier1979 [14.2K]

Answer:

4

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just don’t want to waste my time in case you don’t want me to :)

6 0
3 years ago
Which equation, together with y = -1.5x + 3, makes a system with one solution?
lawyer [7]
The answer I believe would be 2Y + 3x=6
6 0
3 years ago
Exercise 1.A committee of five people is chosen randomly from four men and six women. Find the probability that:a) Exactly four
MatroZZZ [7]

Answer with explanation:

Given : Number of men = 4

Number of women = 6

Total people = 6+4=10

Total number of ways to make a committee of five people from 10 persons :-

^{10}C_{4}=\dfrac{10!}{4!(10-4)!}=210

a) Number of ways to make committee that has exactly four women :

^6C_4\times ^4C_1=\dfrac{6!}{4!(6-4)!}\times4=60

The  probability that committee has exactly four women :

\dfrac{60}{210}=\dfrac{2}{7}

b) Number of ways to make committee that has at-least four women :

^6C_4\times ^4C_1+^6C_5=\dfrac{6!}{4!(6-4)!}\times4+6=66

The probability that committee at-least four women :

\dfrac{66}{210}=\dfrac{22}{70}

c) Number of ways that committee has more than 4 women :-

^6C_5\times^4C_0=6

The probability that committee has more than 4 women :-

\dfrac{6}{210}

Now, the  probability that committee has at most four women :-

1-\dfrac{6}{210}=\dfrac{204}{210}=\dfrac{102}{105}

5 0
3 years ago
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