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3 years ago

Find the length of the hypotenuse left

Mathematics

1 answer:

Allisa [31]3 years ago

3 0

Answer: 2.45

Step-by-step explanation:

I use pythagorean theorem after i found the total of leg A and leg B

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ANYONE KNOW THIS NEED ASAP

Dmitry [639]

B, it’s the point that the lines cross

6 0

2 years ago

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In a circle of radius 10 cm, a sector has an area of 40 (pi) sq. cm. What is the degree measure of the arc of the sector?

Rashid [163]

Answer:

144°

Step-by-step explanation:

First, find the area of the circle, with the formula A = $\pi$ r²

Plug in 10 as the radius, and solve

A = $\pi$ r²

A = $\pi$ (10²)

A = 100 $\pi$

Using this, create a proportion that relates the area of the sector to the degree measure of the arc.

Let x represent the degree measure of the arc of the sector:

$\frac{40\pi }{100\pi }$ = $\frac{x}{360}$

Cross multiply and solve for x:

100 $\pi$ x = 14400 $\pi$

x = 144

So, the degree measure of the sector arc is 144°

6 0

3 years ago

Read 2 more answers

there are 8 students at each of 4 rounds of tables in the cafeteria. there are 64 students at long tables. use the bar model to

Tomtit [17]

Step-by-step explanation:

there should be at least

4 0

3 years ago

If a 10 symbol sequence is sent through the channel,what is the probability that up to 3 symbols are in error out of the 10trans

lina2011 [118]

Answer: 0.171887

Step-by-step explanation:

Given that S0 and S1 are binary symbol of equal probabilty;

P(S0) = P(S1) = 0.5

This probability is a Binomial random variable of sequence Sn, where Sn counting the number of success in a repeated trials.

P(Sn =X) = nCx p^x (1-p)^(n-1)

Pr(at most 3) = P(0<= x <=3) = P(X=0) + 0) + P(X=1) + P(X=2) + P(X=3)

Since there are only 2 values that occur in sequence 0 and 1 ( or S0 and S1).Let the distribution be given by the sequence (0111111111),(1011111111),(11011111111),...(1111111110) for Sn= 1 is the sequence for 1 error.

10C0, 10C1, 10C2, and 10C3 is the number of sequences in value for X= 0, 1, 2, 3 having value 0 and others are 1. Let the success be p(S0)=0.5 and p(S1)= 0.5

P(0<= X <=3) = 10C0 × (0.5)^0 × (0.5)^10 + 10C1× (0.5)¹ × (0.5)^9 + 10C2 × (0.5)² × (0.5)^8 + 10C3(0.5)³(0.5)^7

= 1 × (0.5)^10 + 10 × (0.5)^10 + 45 × (0.5)^10 + 120 × (0.5)^10

=0.000977 + 0.00977 + 0.04395 + 0.11719

= 0.171887

3 0

3 years ago

1. (i) Express 2704 as a product of its prime factors.

lidiya [134]

Answer:

all answers below

Step-by-step explanation:

(i) 2704 = 2^4 x 13^2

(ii) as both indices (the powers) are divisible by 2, it is a perfect square.

(iii) as both indices are not divisible by 3, it is not a perfect square.

8 0

3 years ago