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Rudik [331]
2 years ago
9

Find the length of the hypotenuse left

Mathematics
1 answer:
Allisa [31]2 years ago
3 0

Answer: 2.45

Step-by-step explanation:

I use pythagorean theorem after i found the total of leg A and leg B

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For questions 8 – 10, answer the questions about tangent-tangent angles.
olchik [2.2K]

Answer:

m(arc ZWY) = 305°

Step-by-step explanation:

8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,

Angle formed by two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

                                                   = \frac{1}{2}(220-140)

                                                   = \frac{1}{2}(80)

                                                   = 40°

9). Following the same rule as above,

Angle formed between two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

125 = \frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]

250 = [m(\text{arc ZWY})-m(\text{arc ZY})]

250 = m(arc ZWY) - 55

m(arc ZWY) = 305°

Therefore, measure of arc ZWY = 305° will be the answer.

10). m(arc BAC) = \frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])

                          = \frac{1}{2}(254-106)

                          = \frac{148}{2}

                          = 74°

4 0
2 years ago
The area of a square is (36d^2 - 360d + 9) in^2.
Ber [7]

Answer:

Step-by-step explanation:

36 d²-36 d+9=9(4d²+4d+1)

=9[4d²+2d+2d+1]

=9[2d(2d+1)+1(2d+1)]

=9(2d+1)(2d+1)

=9(2d+1)²

=[3(2d+1)]²

=(6d+6)²

length=6d+6

perimeter=4(6d+6)=24d+24

when d=2

length=6×2+6=18in

perimeter=4×18=72 in

area=18²=324 in²

8 0
2 years ago
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