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4 years ago

What kind of graph is characterized by presenting data values as portions of a circle?

Mathematics

2 answers:

Levart [38]4 years ago

7 0

<span>B. pie chart graph is characterized by presenting data values as portions of a circle </span>

blsea [12.9K]4 years ago

6 0

The correct answer is B. Pie chart

Explanation:

A graph refers to a diagram or image used to represent information, especially numerical data through lines, bars, among others depending on the type of graph. In the case of pie charts, these graphs include a circle that represents the100% of some variables, for example, students in a school, and that is divided into portions to represent specific data, for example, students that like volleyball, soccer, baseball, etc. This graph differs from others because most graphics include two axes, but pie charts only include a circle and portions on it representing data.

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A side of the triangle below has been extended to form an exterior angle of 165º. Find

Arte-miy333 [17]

Answer:

x = 120°

Step-by-step explanation:

the 165 degree obtuse angle forms a straight line with the upper left angle inside the triangle, therefore this angle measures 15 degrees

we know two of the three angle measures so we add all three together to find the unknown angle

x + 15 + 45 = 180

x + 60 = 180

x = 120°

5 0

2 years ago

What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for <em>n </em>:

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$