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3 years ago

What kind of graph is characterized by presenting data values as portions of a circle?

Mathematics

2 answers:

Levart [38]3 years ago

7 0

<span>B. pie chart graph is characterized by presenting data values as portions of a circle </span>

blsea [12.9K]3 years ago

6 0

The correct answer is B. Pie chart

Explanation:

A graph refers to a diagram or image used to represent information, especially numerical data through lines, bars, among others depending on the type of graph. In the case of pie charts, these graphs include a circle that represents the100% of some variables, for example, students in a school, and that is divided into portions to represent specific data, for example, students that like volleyball, soccer, baseball, etc. This graph differs from others because most graphics include two axes, but pie charts only include a circle and portions on it representing data.

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Help please and thank you

Stells [14]

Answer:

Cans 4cans 8 cans 12 cans

Cost $2.25 $4.5 $6.75

Ice Cream 180 q 360 q 540 q 720q 900q 1080 q

Hours 2 hours 4 hours 6 hours 8 hours 10 hours 12 hours

***q = quarts

Distance 650 miles 1300 miles 1950 miles

Hours 3 hours 6 hours 9 hours

8 0

2 years ago

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Reggie earns $12.65 per hour and works 38 hours per week. How much does he earn in a week before taxes are taken out?

vazorg [7]

For a week that he works he would earn $480.70
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7 0

3 years ago

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IM SOO CONFUSEDD help???

lozanna [386]

Answer:

Step-by-step explanation:

To tell whether the domains can include 0, all you need to do is find where x = 0, and whether the y-value is real.

h(x) = sqrt(2x^2 + 5x - 3)

= sqrt(0^2 + 5 * 0 - 3)

= sqrt(-3)

Since this includes the square root of a negative number, h(0) is an imaginary number. That means that we can eliminate choices A and B.

If you look at the graph of w(x), when x = 0, there is a real value for the y-value on the graph. But, if you think about it, if you have 0 workers, there is no way that you can still be producing wrenches. So, the domain cannot contain 0.

Your answer will be D.

Hope this helps!!

3 0

3 years ago

These are all related to geometry and I need help!

nydimaria [60]

SOH-CAH-TOA

sin=opp/hyp

cos=adj/hyp

tan=opp/adj

1. Sin c=opp/hyp 2. tan=opp/adj 3. sin=opp/hyp

sin c=8/17 tan38°=x/16 sin38=18/x

x=18/sin38; x=29.236846

4 0

3 years ago

A maker of a certain brand of low-fat cereal barsclaims that the average saturated fat content is 0.5gram. In a random sample of

finlep [7]

Answer:

$t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386$

$p_v =2*P(t_{(7)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance. So then the claim makes sense

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=0.475$

The sample deviation calculated $s=0.183$

We need to conduct a hypothesis in order to check if the true mean is 0.5 or no, the system of hypothesis would be:

Null hypothesis: $\mu = 0.5$

Alternative hypothesis: $\mu \neq 0.5$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=8-1=7$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(7)}$

Conclusion

4 0

3 years ago

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