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3 years ago

What is the horizontal distance from the plane’s starting position to its finishing position???? I will mark brainliest

Mathematics

1 answer:

Papessa [141]3 years ago

3 0

Answer:

The answer would be 13.3.

Step-by-step explanation:

Use the Pythagorean theorem to find the other distances in the 5, 3, x triangle and the 7, 3, y triangle and add those two answers together plus 3 to get your answer.

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Question Find the x- and y-intercepts of the parabola y = =-3x² - 10x 10. -

algol13

Answer:

-100/3,0

Step-by-step explanation:

substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

if that makes sense Hope this helps pls brainliest have a nice day :>

5 0

2 years ago

Read 2 more answers

A) 60° B) 85° C) 96° D) 40°

RideAnS [48]

Answer:

A)60°

Step-by-step explanation:

a straight line is 180° then

if a line bisect it in to a half it become 90°

then

the exterior angle of a triangle is equal to the sum of two interior angles

this means 150°-90°=60°

8 0

3 years ago

Read 2 more answers

Select the correct answer. What is the domain of the function represented by this graph?

devlian [24]

Answer:

Doman is the x intercpet range

Step-by-step explanation:

all real numbers is the domain since the function goes on and on forever and will at one point get to 1 billion or trillion or just on and on forever.

8 0

3 years ago

Lance measured 0.485 liter of water.Angel measured 0.5 liter of water. Lance said,"My breaker has more water than yours because

Naddika [18.5K]

Answer:

help me

Step-by-step explanation:

8 0

3 years ago

Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot

Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

$\frac{dm}{dt} = -\frac{t}{\tau}$

Where:

$m$ - Current mass of the isotope, measured in kilograms.

$t$ - Time, measured in days.

$\tau$ - Time constant, measured in days.

The solution of the differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

$\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}$

$\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }$

The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

$t_{1/2} = \tau \cdot \ln2$

$t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2$

The half-life difference between isotope B and isotope A is:

$\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|$

If $\frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9$ , $t_{A} = 33\,days$ and $t_{B} = 43\,days$ , the difference in the half-lives of the isotopes is:

$\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|$

$\Delta t_{1/2} \approx 65.788\,days$

The approximate difference in the half-lives of the isotopes is 66 days.

4 0

3 years ago

Read 2 more answers