Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or 
ft
= 
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
= 
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k()
k = 18
Work done (W) to stretch the spring by ft will be
W = 
= 
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9()²
= 7.56 lb-ft
What are the options of tranformation ??/
Let us take the case of 7 pounds for $8.47 first.
7 pounds of a product costs = 8.47 dollars
Then
1 pound of the same product will cost = (8.47/7) dollars
= 1.21 dollars
Now let us take the case of 9 pounds for $11.07
9 pounds of a product costs = 11.07 dollars
Then
1 pound of the same product will cost = (11.07/9) pounds
= 1.23 dollars
So from the above deductions we can see that 9 pounds for $11.07 is a better buy than 7 pounds for $8.47. I hope the procedure is clear enough for you to understand. In future you can use this method for solving similar problems.
Answer:
84
Step-by-step explanation:
is x 140
---- SO ... ------- = --------
of 60 100
(hit like pls)
60*140=100x
8400=100x
/100 /100
-------------------
84 = x
<h3>
Answer: Choice C</h3>
The base 16 is the same as 4*4.
From there, the rule 
is used to get 
Afterward, the exponents are added getting 1/2+1/2 = 2/2 = 1. The rule is 
which only works if the bases are both the same.
