Answer:
first one is 90
second one is 108
Step-by-step explanation:
If the question is to find the slope-intercept form of both lines, here's the answer:
Both lines pass through the point (-3,-4), so we can use these coordinates in both equations. The slope-intercept form is represented by y=mx+b, with m the slope, b the intersection of the line with Y'Y for x=0, y and x the coordinates of a point.
Let's first apply all these for the first line, with a slope of 4.
y = mx + b
y=-3; x=-4; m=4. All we need to do is find b.
-3 = 4(-4) + b
-3 = -16 + b
b=13
So the equation of the first line is y= 4x + 13.
Now, we'll do the same thing but for the second line:
y=-3; x=-4; m=-1/4, and we need to find b.
-3 = (-1/4)(-4) + b
-3 = 1 + b
b= -4
So the equation of the second line is y=(-1/4)x - 4
Hope this Helps! :)
Hello :
<span>y = –2x – 1....(1)
y = 3x–1.....(2)
by (1) and (2) : 3x-1 = -2x-1
5x =0
x =0 ....(</span><span>the x-coordinates of the solutions)</span>
Answer:
Step-by-step explanation:
jx(W)
The answer I believe is c
