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larisa [96]
3 years ago
13

HELP SOMEONE PLEASE !!!

Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

I dont know

Step-by-step explanation:

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Find the value of side a on the right triange, given that side B=12cm and side C=15cm
docker41 [41]
Use Pythagoras's theorem.
a^{2} + b^{2} = c^{2}

Now, minus 12 from 15:
15 - 12 = 3,
which you need to square.
So the length of a = 9cm.

You can also do:
\sqrt{15^{2} - 12^{2} }
Which gets 9.

Hope this helps.

3 0
3 years ago
Can y’all help me on question 35?!
Nikolay [14]

Answer:

c

Step-by-step explanation:

C becasue 1 week = 15 mulitipication facts memorized

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3 years ago
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According to Reuters, a survey undertaken by the National Center for Health Statistics revealed that about 25% of U.S. household
ddd [48]

Answer:

a) P=0.8

b) P=0.67

c) P=0.05

d) P=0.33

e) P=0.45

Step-by-step explanation:

a. What is the probability that the household has only a cell phone and has high-speed Internet?

This probability is stated in the question: "Suppose of U.S. households having only a cell phone, 80% have high-speed Internet", so the probability is P=0.8.

P(C\&I)=0.8

b. What is the probability that the household has only a cell phone or has high-speed Internet?

This probability is equal to the sum of the probability of having only a cell phone and the probability of having high-speed internet, less the probability of having both (to avoid counting this household twice).

P(C\,orI\,)=P(C)+P(I)-P(C)*P(I|C)=0.25+0.65-(0.25*0.8)=0.25+0.62-0.20=0.67

c. What is the probability that the household has only a cell phone and does not have high-speed Internet?

This is equal to the probability of not having high-speed internet given that it has a cell phone (complementaty of the proability of Point (a)) multiplied by the probability of having a cell phone.

P(C\&\bar I)=P(\bar I|C)*P(C)=(1-P(\I|C))*P(C)=(1-0.8)*0.25 = 0.2*0.25 = 0.05

d. What is the probability that the household does not have just a cell phone and does not have high-speed Internet?

This probability is complementary of the one calculated in Point (c).

P(\bar C \,or\, \bar I)=1-P(C\, or\,I)=1-0.67=0.33

e. What is the probability that the household does not have just a cell phone and does have high-speed Internet?

This is equal to the probability of having high-speed internet less the probability it has both (cell phone and internet).

P(\bar C\&I)=P(I)-P(I|C)*P(C)=0.65-0.8*0.2=0.65-0.2=0.45

7 0
4 years ago
PLEASE HELP!!!!
SCORPION-xisa [38]

Answer:

2 x c7 = 5

Step-by-step explanation:

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