Question

Can someone please help me out

Answer 1

Answer:

$W =2 {y}^{3} \: \:meters$

Step-by-step explanation:

The figure is a rectangle whose area can be calculated from the relation;

$A = L \times W$

where A , L and W represent the area, length and width respectively.

From the question,

$A = 60 {y}^{4}$

and L=30y meters

We substitute the values of A and L into the formula to solve for W

$\implies60 {y}^{4} = 30y \times W$

Dividing through by 30y

$\implies\frac{60 {y}^{4}}{30y}= \frac{30y \times W}{30y}$

$\implies W =2 {y}^{3} \: \:meters$

NB: From the law of indices;

$\frac{ {y}^{4} }{y}= {y}^{(4 - 1)}={y}^{3}$