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Kisachek [45]
3 years ago
9

Find the equation of the line perpendicular to x−5y=15 that passes through the point (−2,5).

Mathematics
1 answer:
defon3 years ago
7 0

Answer:

Step-by-step explanation:

-5y = -x + 15

5y = x - 15

y = 1/5x - 3

perp. -5

y - 5 = -5(x + 2)

y - 5 = -5x - 10

y = -5x - 5

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Given equations:

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   y = 3x + 2    ----- (i)

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Using substitution method, input equation i, into ii

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