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Zielflug [23.3K]
3 years ago
15

What is the domain of the function f(x) = 4x-16 ?

Mathematics
2 answers:
Svetach [21]3 years ago
7 0

The domain is x-values that work in the equation, and in this case, the domain is all real numbers, as any number you put in will give you a number back out.

Goshia [24]3 years ago
3 0

Answer:

All real numbers

Step-by-step explanation:

The domain is every value you can put in for x, and since you are able to put in any real number, the domain is all real numbers.

You might be interested in
#14 i
ivann1987 [24]

Answer:

Incorrect/No

Step-by-step explanation:

7x2=14

-7x2=-14

<u>Follow the below guidelines:</u>

  • A positive number times a positive number is a positive number
  • A negative number times a positive number is a negative number
  • A positive number times a negative number is a negative number
  • A negative number times a negative number is a positive number

Looking at the last one, we see that -2x-7=14, a positive number

Hope this helps!

--Applepi101

7 0
3 years ago
Given: mAngleEDF = 120°; mAngleADB = (3x)°; mAngleBDC = (2x)° Prove: x = 24 3 lines are shown. A line with points E, D, C inters
N76 [4]

Answer:

" Vertical angles are congruent " ⇒ 2nd answer

Step-by-step explanation:

* <em>Look to the attached figure </em>

- There are three lines intersected at point D

- We need to find the missing in step 3

∵ Line FA intersects line EC at point D

- The angles formed when two lines cross each other are called

 vertical angles

- Vertical angles are congruent (vertical angles theorem)

∴ ∠ADC and ∠FDE are vertical angles

∵ Vertical angles are congruent

∴ ∠EDF ≅ ∠ADC

∴ m∠EDF ≅ m∠ADC

∵ m∠EDF = 120° ⇒ given

∵ m∠ADC = m∠ADB + m∠BDC

∴ m∠ADB + m∠BDC = 120°

∵ m∠ADB = (3x)° ⇒ given

∵ m∠BDC = (2x)° ⇒ given

∴ 3x + 2x = 120 ⇒ add like terms

∴ 5x = 120 ⇒ divide both sides by 5

∴ x = 24

Column (1)                                                     Column (2)

m∠EDF = 120°                                               given

m∠ADB = 3 x                                                 given

m∠BDC = 2 x                                                 given

∠EDF and ∠ADC are vertical angles           defin. of vert. ∠s

∠EDF is congruent to ∠ADC                        vertical angles are      

                                                                        congruent  

m∠ADC = m∠ADB + m∠BDC                        angle add. post.

m∠EDF = m∠ADC                                          defin. of cong.

m∠EDF = m∠ADB + m∠BDC                         substitution

120° = 3 x + 2 x                                               substitution

120 = 5 x                                                         addition

x = 24                                                              division  

∴ The missing reason is " vertical angles are congruent "

- From the explanation above ∠ADC and ∠FDE are vertical

 angles then they are congruent according to vertical angle

 theorem

6 0
3 years ago
Read 2 more answers
Solve 1/2cot(x)&gt;=1/2 over 0&lt;=x&lt;=2pi
RSB [31]

9514 1404 393

Answer:

  (0, π/4] ∪ (π, 5π/4]

Step-by-step explanation:

Multiplying by 2 gives ...

  cot(x) ≥ 1

The cotangent function decreases from ∞ to 1 in the domain (0, π/4], and again in the domain (π, 5π/4]. The solution is the union of these two intervals.

  x ∈ (0, π/4] ∪ (π, 5π/4]

_____

(a, b] is interval notation for a < x ≤ b

3 0
3 years ago
Evaluate 5x3 - 21 + 7 when x = -2.
Sliva [168]

Answer:

26

Step-by-step explanation:

5x³ - 21 + 7

x = 2

then:

5x³ - 14

5*2³ -14

5*8 - 14

40 - 14

26

8 0
3 years ago
Read 2 more answers
In London today, four times the high temperature was more than twice the high temperature plus
4vir4ik [10]

Answer:

Let's define the high temperature as T.

We know that:

"four times T, was more than 2*T plus 66°C"

(i assume that the temperature is in °C)

We can write this inequality as:

4*T > 2*T + 66°C

Now we just need to solve this for T.

subtracting 2*T in both sides, we get:

4*T - 2*T > 2*T + 66°C - 2*T

2*T > 66°C

Now we can divide both sides by 2:

2*T/2 > 66°C/2

T > 33°C

So T was larger than 33°C

Notice that T = 33°C is not a solution of the inequality, then we should use the symbol ( for the set notation.

Then the range of possible temperatures is:

(33°C, ...)

Where we do not have an upper limit, so we could write this as:

(33°C, ∞°C)

(ignoring the fact that ∞°C is something impossible because it means infinite energy, but for the given problem it works)

4 0
3 years ago
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