A^2+b^2=c^2
A=63
B=?
C=87
63^2+b^2=87^2
3969+b^2=7569
-3969 both sides
B^2=3600
Square root both sides
B=60in
Let us assume the larger number = x
Let us assume the smaller number = y
Then
x + y = 3 3/4
x + y = 15/4
And
x/3 = (2y/3) + 1/2
x = [3 * (2y/3)] + (3/2)
= 2y + (3/2)
Now putting the value of x from the second equation to the first , we get
x + y = 15/4
2y + (3/2) + y = 15/4
3y = (15/4) - (3/2)
3y = (15 - 6)/4
3y * 4 = 9
12y = 9
y = 9/12
= 3/4
Now putting the value of y in the first equation, we get
x + y = 15/4
x + (3/4) = (15/4)
x = (15/4) - (3/4)
= (15 - 3)/4
= 12/4
= 3
So the value of x or the larger number is 3 and the value of y or the smaller number is 3/4.
The correct answer is: 44.1ft - 46ft = -1.9ft/44.1ft = .043% relative error. Please mark Brainliest if helpful
Answer:
The base of the ladder is 2.58 m.
Step-by-step explanation:
Given that,
The angle of elevation for a ladder from the ground is 75°.
The length of a ladder, H = 10 foot
We need to find the distance from the house should you place the base of the latter. Let the base of the ladder is b. Using trigonometry,
So, the base of the ladder is 2.58 m.
