Answer:
70
Step-by-step explanation:
it depends on the grade you make, so if you were to make a 65.47, your grade would be a 70, so any grade less than 70 should be the answer, hope this helps!
Tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)*(tan b) ];
let be a = 2x and b = x;
=> tan 3x = [ tan 2x + tan x ] / [ 1 - (tan 2x)*(tan x) ] => (tan 3x)*[ 1 - (tan 2x)*(tan x) ] =
tan 2x + tan x => tan3x - tan 3xtan 2xtanx = tan 2x + tan x => <span> tan 3x−tan 2x−tanx = tan 3xtan 2xtanx.</span><span />
You should expect
5. There is one grey marble out of 9 total, and that can be expressed as 1/9. Since you repeat it 45 times, it's
1/9 45 times, or 1/9(45).

1*45 is 45
9*1 is 9.
45/9 is
5.
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Be sure to choose which answer is Brainliest!</em>
Answer:
(A) The odds that the taxpayer will be audited is approximately 0.015.
(B) The odds against these taxpayer being audited is approximately 65.67.
Step-by-step explanation:
The complete question is:
Suppose the probability of an IRS audit is 1.5 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more.
A. What are the odds that the taxpayer will be audited?
B. What are the odds against such tax payer being audited?
Solution:
The proportion of U.S. taxpayers who were audited is:
P (A) = 0.015
Then the proportion of U.S. taxpayers who were not audited will be:
P (A') = 1 - P (A)
= 1 - 0.015
= 0.985
(A)
Compute the odds that the taxpayer will be audited as follows:


Thus, the odds that the taxpayer will be audited is approximately 0.015.
(B)
Compute the odds against these taxpayer being audited as follows:


Thus, the odds against these taxpayer being audited is approximately 65.67.