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Novosadov [1.4K]
3 years ago
10

Please help!!!!!! We haven't gone over this in class yet!

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

A C and D

Step-by-step explanation:

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Solve the equation 6(x + 2) = 3(2x + 4).How many solutions are there? Show your work ​
Naily [24]
6(x + 2) = 3(2x + 4)
STEP ONE:
Multiply both sides
6x + 12 = 6x + 12
STEP TWO:
You can see both sides are identical, therefore you can conclude there are infinite solutions

ANSWER: Infinite Solutions
6 0
3 years ago
This is VERY URGENT, so 50 points if you answer correctly!
mariarad [96]

Answer:

The circumference is 31.43 cm

The ratio of the circumference to the diameter is equal to 3:1

Step-by-step explanation:

Thed formular for the circumference of a circle is 2\pir or \pid

where d = diameter and r = radius

if d = 10 cm, and \pi = 3.143, then circumference of the circle can be given as

3.143*10 = 31.43 cm

The ratio of the circumference to the diameter can be given as 31.43:10

and that can be given as 3.143:1

or 3:1, for the nearest whole number

3 0
4 years ago
1.
malfutka [58]

Answer:

<h2>5 units</h2>

Step-by-step explanation:

A right angled triangle is a triangle that has one of this angles to be 90°. According to the ΔABC, the angle at B is 90°.

Area of a triangle = 1/2 * base * height

According to the diagram shown, the base is BC and the height is AB which is the required side.

Area of the triangle = 1/2 * BC * AB

Given area of the triangle = 10 square units

BC = 4 units

AB is the required length.

Substituting this values into the formula above;

10 = 1/2 * 4 * AB

10 = 2AB

Dividing both sides by 2

2AB/2 = 10/2

AB = 5 units

Hence the length of AB is 5 units.

4 0
3 years ago
Which of the following sets of numbers between 12 and 20 contains only prime numbers .
topjm [15]

Answer:

13, 17, 19

Step-by-step explanation:

Go through (12-20) and find the multipliers for each number.

13 = 13 x 1

14 = 7 x 2 , 14 x1 = no

15 = 5 x 3, 15 x 1 = no

17 = 17 x 1

18 = 6 x 3, 9 x 2, 18 x 1 = no

19 = 19 x 1

4 0
3 years ago
Let T: Rn → Rn be an invertible linear transformation, and let S and U be functions from Rn into Rn such that
ipn [44]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

T: 1 \ R^n \to  1 \ R^n is invertible lines transformation

S[T(x)]=x \ and \ V[T(x)]=x \\\\t'x \  \varepsilon\ 1 R^n\\\\

T is invertiable linear transformation means that is  

T(x) =A x \\\\ where \\\\ A= n \times n \ \ matrix

and \ det(A) \neq 0 \ \ that \ is \ \ A^{-1} \ \ exists

Let

V \varepsilon\  a\  R^{n} \ consider \ \ u= A^{-1} v \varepsilon 1 R^n\\\\T(u)= A(A^{-1} v)=(A \ A^{-1}) \\\\ v= I_{n \times n} \cdot v = v

so,  

s[T(u)]=v[T(u)]\\\\s(v)=v(v) \ \  \forall \ \ v \ \ \varepsilon \ \ 1 R^n

7 0
3 years ago
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