Question

Alamo is building a set of 4 shelves each shelve will have 2 supporters in the shape of right isosceles triangles. Each shelf is 14 inches deep. How many square inches of wood will she need to make all of the supports

Answer 1

Answer:

The correct answer is 784 square inches.

Step-by-step explanation:

Depth of each shelf made by Alamo is 14 inches.

So the base of the right isosceles triangular supporter is 14 inches.

So one equal side is 14 cm. Now by using Pythogoras theorem we can calculate the other side of the supporter = $\sqrt{14^{2} + 14^{2}}$ = 19.8 inches.

Area of the right isosceles triangle is given by $\frac{1}{2}$ × base ×height. Here the base and height are equal to 14 inches.

Therefore area of each right isosceles triangular supporter is

$\frac{1}{2}$ × 14 × 14 = 98 square inches.

Each shelf would require two such supporters and there are 4 such shelves. Thus total number of supporters required are 8.

Square inches of wood necessary for 8 right isosceles triangular supporters = 98 × 8 = 784 square inches.