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3 years ago

What are some true statements about a circle circumference

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

8 0

Isn’t it pie or something idk

goldenfox [79]3 years ago

5 0

Answer:

1. Circumference is the enclosing boundary of a curved geometric figure, especially a circle

2. Circumference is the distance around something.

3. Circumference is found using 2pi times radius

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6) 2(n + 5) = -2 help i wasn’t paying attention in my google meet

bonufazy [111]

Answer: the answer is -6

2(n+5) = -2

2n + 10 = -2

2n = -2 - 10

2n = -12

2n *1/2 = -12 * 1/2 = -6

n = -6

5 0

3 years ago

Read 2 more answers

A man earns$140 in 5 day week. What is his pay for 3 days?

Flura [38]

Answer:

$84

Step-by-step explanation:

Do 3/5*140 which will give you 84 dollars

4 0

3 years ago

Consider the following set of ages of students is a college seminar.

jonny [76]

Answer:

1) $\sum\limits_{i=2}^{6}x_{i}=116$

2) $\sum\limits_{i=1}^{4}x_{i}=87$

Step-by-step explanation:

Given that $x_{1}=21,x_{2}=23,x_{3}=22,x_{4}=21,x_{5}=24,x_{6}=26,x_{7}=28$

1) Given that $\sum\limits_{i=2}^{6}x_{i}$

To find $\sum\limits_{i=2}^{6}x_{i}$

Expanding the sums below to solve it

$\sum\limits_{i=2}^{6}x_{i}=x_{2}+x_{3}+x_{4}+x_{5}+x_{6}$

$=23+22+21+24+26$ (adding the terms )

$=116$

Therefore $\sum\limits_{i=2}^{6}x_{i}=116$

2) Given that $\sum\limits_{i=1}^{4}x_{i}$

To find $\sum\limits_{i=1}^{4}x_{i}$

Expanding the sums below to solve it

$\sum\limits_{i=1}^{4}x_{i}=x_{1}+x_{2}+x_{3}+x_{4}$

$=21+23+22+21$ (adding the terms )

$=87$

Therefore $\sum\limits_{i=1}^{4}x_{i}=87$

6 0

3 years ago

If anyone is good at geometry, pls help :)

Vadim26 [7]

Answer:

Segment Addition Postulate

BC + AB = CA [BOTH answers]

Application with Midpoint

BC = BA

1a) 9 = x

1b) 34 = FA

1c) 3 = AT

2a) 11 = x

2b) 37 = BO

2c) 37 = OX

2d) 74 = BX

Step-by-step explanation:

The Segment Addition Postulate is basically saying that if

___

point B is in between AC [NOT the midpoint (or halfway)], then both segments [AB and BC] would make up the whole thing [CA, or vice versa]. They are just explaining it in two unique ways you can word it.

The Midpoint Application tells you that if point B is a

___

midpoint, meaning B is halfway in between AC, then both segments [AB and BC] are congruent to each other.

1a) 37 = [2x - 15] + [3x + 7]

37 = 5x - 8

+ 8 + 8

____________

45 = 5x

___ ___

5 5

9 = x

1b) Solving for FA

$3(9) + 7 = 27 + 7 = 34$

1c) Solving for AT

$2(9) - 15 = 18 - 15 = 3$

This obviously had to be the answer because 3 + 34 = 37.

2a) 2x +15 = 4x - 7

- 4x - 4x

_________________

-2x + 15 = -7

- 15 -15

_____________

-2x = -22

x = 11

2b) Solving for BO

$4(11) - 7 = 44 - 7 = 37$

2c) Solving for OX

$2(11) + 15 = 22 + 15 = 37$

2d) Solving for BX

$2 \times 37 = 74$

I am joyous to assist you anytime.

4 0

4 years ago

PLEASE HELP!!! 15 PTS!!

kherson [118]

Answer:

$\large\boxed{C.\ (2,\ -45^o)}$

Step-by-step explanation:

Regular coordinates (x, y)

Polar coordinates (r, φ)

$r=\sqrt{x^2+y^2}\\\\\psi=\arctan\frac{y}{x}$

We have the point

$(\sqrt2,\ -\sqrt2)$

Substitute:

$r=\sqrt{(\sqrt2)^2+(-\sqrt2)^2}=\sqrt{2+2}=\sqrt4=2\\\\\psi=\arctan\left(\frac{-\sqrt2}{\sqrt2}\right)=\arctan(-1)=-45^o$

6 0

3 years ago