1) given x^4 + 95x^2 - 500
2) split in two factors with common factor term x^2: (x^2 + )(x^2 - )
3) find two numbers that add up 95 and their product is - 500:
=> 100*(-5) = - 500 and 100 - 5 = 95
=> (x^2 + 100)(x^2 - 5)
4) factor x^2 - 5 = (x + √5) (x - √5)
5) write the prime factors: (x^2 + 100) (x + √5) (x -√5)
6) find the solutions:
x^2 + 100 = 0 => not possible
x + √5 = 0 => x = - √5
x - √5 = 0 => x = √5
Answer: x = √5 and x = - √5
Answer:
3x+2Y=10
6×-5-1×=0
Step-by-step explanation:
6-5-1=0
Answer:
67.5
Step-by-step explanation:
Answer:
No, it isn't.
Step-by-step explanation:
Pythagorean theorem is x^2 + y^2 = z^2.
6^2 + 8^2 = 9^2
36 + 64 = 81
100 = 81
So, it isn't.
