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2 years ago

13

Explain how you can find the constant of proportionality from a graph representing a proportional relationship when it shows a p

oint with an x - value of 1 and if it doesn't show an x - value of 1 .

1 answer:

Vladimir [108]2 years ago

8 0

tienees que fijartelos extrreemos

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The 44 members of the glee club are trying to raise at least $6,000 so they can compete in the state

bagirrra123 [75]

Answer:

The inequality 44x + 1230 ≥ 6000 can be used.

Step-by-step explanation:

Number of members = 44

Amount to raise = $6000

Amount already raised = $1230

Let,

x be the amount each member needs to raise.

44x + 1230 ≥ 6000

Therefore,

The inequality 44x + 1230 ≥ 6000 can be used.

3 0

2 years ago

I will mark as the brainliest answer

Hunter-Best [27]

ratio for the first mix is 3:2 the ratio for the second mix is 4.5:3

Yes, since 3 times 1.5 is 4 and 2 times 1.5 is 3

6 0

3 years ago

Carlotta thinks that 3y + 5y3 is the same as 8y4. Which statement shows that it is NOT the same?

Vesna [10]

Answer:

C. 3(4) + 5(4)³ ≠ 8(4)⁴

Step-by-step explanation:

3y + 5y³ is NOT the same as 8y⁴

Assume y = 4

Not equal to sign ≠

3y + 5y³ ≠ 8y⁴

3(4) + 5(4)³ ≠ 8(4)⁴

12 + 20³ ≠ 32⁴

12 + 8000 ≠ 1,048,576

8012 ≠ 1,048,576

The statement which shows that 3y + 5y³ is NOT the same as 8y⁴ is 3(4) + 5(4)³ ≠ 8(4)⁴

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cbegin%7Bbmatrix%7D%20%5Cbegin%7Barray%7D%20%7B%20l%20l%20%7D%20%7B%202%20%7D%20%

SVETLANKA909090 [29]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

$\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)$

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)$

The remaining elements of the product matrix are found in the same way.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)$

Simplify each element by multiplying the individual terms.

$\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)$

Now, sum each element of the matrix.

$\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}$

7 0

2 years ago

Write each as a decimal. Round to the thousandths place.<br> 9) 78.4%<br> 10) 29%<br> Help

fomenos

Answer:

$(a) 78.4\% = 0.784$

$(b) 29\% =0.290$

Step-by-step explanation:

Required

As a decimal to nearest thousandth

Solving (a): 78.4%

$78.4\%$

Express as fraction

$78.4\% = \frac{78.4}{100}$

Solve fraction

$78.4\% = 0.784$ ----- This is already in thousandth place

Solving (b): 29%

$29\%$

Express as fraction

$29\% =\frac{29}{100}$

Solve fraction

$29\% =0.29$

Approximate

$29\% =0.290$

4 0

3 years ago