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user100 [1]
3 years ago
15

Marcus is 5 7/24 feet tall Ben is 5 5/16 feet tall which of the two boys is taller? Justify your answer

Mathematics
2 answers:
FromTheMoon [43]3 years ago
5 0
To figure out who is taller, we can take each mixed number and find a common denominator.

5/16 (x3) 15/48
7/24 (x2) 14/48

This tells us that Ben is taller because Marcus is shorter than him by 1/48.
Wittaler [7]3 years ago
3 0

Answer:

Ben is taller than Marcus

Step-by-step explanation:

Height of Marcus = 5\frac{7}{24}feet

To write this mixed fraction in decimal the we need to split it and add the two terms-

5\frac{7}{24} = 5 + \frac{7}{24} = 5 + 0.291 = 5.291

∴Height of Marcus = 5.291feet

Height of Ben = 5\frac{5}{16}feet

Similarly we can write this also in decimal as-

5\frac{5}{16} = 5 + \frac{5}{16} = 5 + 0.313= 5.313

∴Height of Ben= 5.313feet

∴ Ben is taller than Marcus

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Angles R and S are complementary. If angle R is = 4x - 20 and angle S = 6x - 7, then angle R measures ___ degrees.
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26.8°

Step-by-step explanation:

4x - 20 + 6x - 7 = 90

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= 46.8-20 = 26.8°

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Thepotemich [5.8K]

Answer:

ok so first you have to know what a reflectiin along 180 is

) A point P(x,y)P(x,y) is rotated 180180 degrees about the origin, then reflected over the y-axis. What is the resulting image of PP?

My conjecture: (−x,y)(−x,y) but I don't quite agree with it graphically. I'm having trouble with what exactly a 180 degree rotation about the origin simply is.

2) A point P(x,y)P(x,y) is reflected over the y-axis and then rotated 180 degrees about the origin. What is the resulting image?

Is this the same thing as 1?

3) A point A(x,y)A(x,y) is reflected over the line y=xy=x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (−y,x)(−y,x)

4) A point A(x,y)A(x,y) is reflected over the lines y=−xy=−x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (y,−x)

ok you need to know what thouse meen

Step-by-step explanation:

)If P(x1,y1)P(x1,y1) is rotated angle ϕϕ about O(a,b)O(a,b) to P′(x′,y′)P′(x′,y′)

we have |OP|=|OP′||OP|=|OP′| and |arctanmOP−arctanmOP'|=ϕ|arctan⁡mOP−arctan⁡mOP'|=ϕ

By atan(z)(z) I imply atan2

(2)If P(x1,y1)P(x1,y1) is reflected over L:ax+by+c=0L:ax+by+c=0 and the resulting image of PP is Q(x2,y2)    (1)Q(x2,y2)    (1)

We have R

so i hope thiz helprs you

3 0
3 years ago
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