The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
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You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Put this into slope intercept form.
y = 6 - x becomes y = -x + 6
"m" is the coefficient on x: -1
"c" is the number without the x: 6
Answer:
0.03
Step-by-step explanation:
There are two 0s so it is 0.03
Answer:
2√(17) or about 8.2462 units.
Step-by-step explanation:
We want to determine the distance between the two points (-10, -7) and (-8, 1).
We can use the distance formula. Recall that:
Substitute and evaluate:
Hence, the distance between (-10, -7) and (-8, 1) is 2√(17) units or about 8.2462 units.
The answer to your question would be D.
there is no way to tell if any of the other options are true or not so the only possible choice would be D.
Hope this helps! :)
