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3 years ago

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After the math contest, Badil noticed that there where four extra large pizzas that where left untouched. In addiction, another

3 slices of pizza where uneaten. If there where a total of 51 slices of pizza left, how many slices does an extra large pizza have?

1 answer:

Sphinxa [80]3 years ago

4 0

51-3=48 slice.
48 slice/ 4 pizza= 12 slice
each extra large pizza have 12 slice.

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6) If the value of x in the above diagram equals 26, which of the following pairs of numbers does the solution fall between?

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I am pretty sure it is D not sure though

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Ryleigh receives her pay monthly. Her deductions include $112 in Federal Income Tax, State Tax of 3.5% of gross, City Tax of 2.5

vodka [1.7K]

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Answer:

$6,106.87

Step-by-step explanation:

The total of percentage deductions is ...

state tax + city tax + social security + medicare

= 3.5% +2.5% +6.2% +1.45% = 13.65%

Then Ryleigh's take-home pay is ...

gross(1 -13.65%) -112 = 5161.28

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Ryleigh's monthly gross is $6,106.87.

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Different dealers may sell the same car for different prices. The sale prices for a particular car are normally distributed with

Stels [109]

Answer:

P(X > 25) = 0.69

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The sale prices for a particular car are normally distributed with a mean and standard deviation of 26 thousand dollars and 2 thousand dollars, respectively.

This means that $\mu = 26, \sigma = 2$

Find P(X>25)

This is 1 subtracted by the pvalue of Z when X = 25. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 26}{2}$

$Z = -0.5$

$Z = -0.5$ has a pvalue of 0.31

1 - 0.31 = 0.69.

So

P(X > 25) = 0.69

4 0

3 years ago

supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are

Simora [160]

<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

$\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu$

, where n= sample size

$\overline{x}$ = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : $df=n-1=24$

$\overline{x}= \$93.36$

$s=\ $19.95$

Significance level for 98% confidence interval : $\alpha=1-0.98=0.02$

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

$t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922$

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

$93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu$

$=93.36-9.943878< \mu$

$=93.36-9.943878< \mu$

$=83.416122< \mu$

Hence, the 98% confidence interval for the mean repair cost for the dryers. = $83.4161$

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3 years ago