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blsea [12.9K]
3 years ago
11

Solve this step by step solution please

Mathematics
1 answer:
mestny [16]3 years ago
6 0

Answer:

the equation does not have like terms so it cannot be simplified further that's it is at its simplest form.

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Please help me out thank you.​
s2008m [1.1K]

its A

Step-by-step explanation:

6 0
3 years ago
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In order to solve the equation −3x + 6 = 5, the first step is to (1 point)
aliya0001 [1]
   −3x + 6 = 5  | -6   (first step is: "subtract 6 from both sides" <span>)
</span>
-3x = 5-6
-3x = -1      |  /(-3)   (second step is: "<span>divide by (-3) on both sides</span>" <span>)


</span>\displaystyle  \\ &#10;x =  \frac{-1}{-3} =  \boxed{\frac{1}{3} }
<span>

</span>
5 0
3 years ago
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I am ust typing this so it will let me post this But Please Help
andre [41]

Answer:

{4}^{3}  = 64

Step-by-step explanation:

\frac{ {4}^{8} }{ {4}^{5} }  =  {4}^{3}

Subtract the numerator exponent from the denominator exponent.

8 - 5

4 0
3 years ago
Camille bought 3 pounds of nuts for 10.35. What is the unit price per pound?
dusya [7]
3.45. All you have to do is divide 10.35 by 3.
8 0
3 years ago
Read 2 more answers
The amount of polonium-210 remaining, p(t), after t days in a sample can be modeled by the exponential function p(t) = 100e−0.00
Archy [21]

Answer:

% Po lost = 100[1 - e^(-0.005t)]  %; 73.0 g

Step-by-step explanation:

p(t) = 100e^(-0.005t)

Initial amount:        p(0) = 100

Amount remaining: p(t) = 100e^(-0.005t)

Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]

% of Po lost  = amount lost/initial amount × 100 %

= [1 - e^(-0.005t)]  × 100 % = 100[1 - e^(-0.005t)]  %

p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g

The mass of polonium remaining after 63 days is 73 g.

4 0
3 years ago
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