Answer:
Kindly check explanation
Step-by-step explanation:
Given that:
X = 1, 6, 2, 3
Find sum ∑ X2
∑ X^2 = ∑ (1^2 + 6^2 + 2^2 + 3^2)
∑ X^2 = ∑ ( 1 + 36 + 4 + 9)
∑ X^2 = 50
Second tak task is unclear
Find sum ∑ (X-3)
X = 1, 6, 2, 3
∑ X - 3 = ∑ (1-3) + (6-3) + (2-3) + (3-3)
∑ (X-3) = ∑ (-2 + 3 + - 1 + 0
∑ (X-3) = ∑ (-2 + 3 - 1 + 0)
∑ (X-3) = 0
Find the sum ∑ (X-3)^2
X = 1, 6, 2, 3
∑ (X-3)^2 = ∑ (1-3)^2 + (6-3)^2 + (2-3)^2 + (3-3)^2)
∑ (X-3)^2 = ∑ (-2^2 + 3^2 + (-1^2) + 0
∑ (X-3)^2 = (4 + 9 + 1)
∑ (X-3)^2 = (14)