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olasank [31]
3 years ago
5

Given h(x) = x^ - 2, what is the value of h(-3) ? ^ = is exponent 2

Mathematics
2 answers:
raketka [301]3 years ago
5 0

Answer:

h(-3) = 7

Step-by-step explanation:

h(x) = x^2 - 2

h(-3) = (-3)^2 - 2

h(-3) = 9 - 2

h(-3) = 7

Best of Luck!

ella [17]3 years ago
3 0

Answer:

  • 1/9

Step-by-step explanation:

<u>Given</u>

  • h(x) = x^ - 2
  • h(-3) = ?

<u>Substitute x with -3</u>

  • h(-3) = (-3)^-2 = 3^-2 = 9^-1 = 1/9
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3 years ago
Y=x^2 -9x at x = 4 Find an equation of the tangent an an equation of the normal
Montano1993 [528]

The tangent line to <em>y</em> = <em>f(x)</em> at a point (<em>a</em>, <em>f(a)</em> ) has slope d<em>y</em>/d<em>x</em> at <em>x</em> = <em>a</em>. So first compute the derivative:

<em>y</em> = <em>x</em>² - 9<em>x</em>   →   d<em>y</em>/d<em>x</em> = 2<em>x</em> - 9

When <em>x</em> = 4, the function takes on a value of

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Then use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-20) = -1 (<em>x</em> - 4)

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<em>y</em> = -<em>x</em> - 24

The normal line is perpendicular to the tangent, so its slope is -1/(-1) = 1. It passes through the same point, so its equation is

<em>y</em> - (-20) = 1 (<em>x</em> - 4)

<em>y</em> + 20 = <em>x</em> - 4

<em>y</em> = <em>x</em> - 24

3 0
3 years ago
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