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3 years ago

Pls need help immediately, nd can can u explain it too

Mathematics

2 answers:

tigry1 [53]3 years ago

3 0

The answer is 18...
(3 / 8 ) * 48 = 18

defon3 years ago

3 0

3/8 × 48 =
144/8 = 18

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Plzz help me I am helpless

horrorfan [7]

Answer: 0.25

<u>Step-by-step explanation:</u>

You need to convert the cm³ into m³

$\frac{250,000(cm)(cm)(cm)}{}* \frac{1(m)}{100(cm)} * \frac{1(m)}{100(cm)}* \frac{1(m)}{100(cm)} = \frac{250,000m^{3}}{1,000,000}$

= .25 m³ per m²

6 0

3 years ago

Read 2 more answers

PLEASE HELP WILL MARK BRAINLIEST!!!!

Lyrx [107]

Answer:

y = -5x + 20

Step-by-step explanation:

Lets start with the first given values for x and y

(2,10)

Lets try out the first equation

y = 5x + 4

y = 5(2) + 4

y = 14

This equation wouldn't work because the y value is not 10 when the x value is 2

y = 5x + 20

y = 5(2) + 20

y = 30

This equation doesn't work either

y = -5x + 20

y = -5(2) + 20

y = -10 + 20

y = 10

This would be the correct equation since your y value is 10 when the x value is 2

5 0

3 years ago

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A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4

Vladimir79 [104]

Answer:

The time interval when $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

$V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)$

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

$V_Q(t) \geq 60$ between $0 \leq t \leq 4$

The schematic free body graphical representation of the above illustration was attached in the file below and the point when $V_Q(t) \geq 60$ is at 4 is obtained in the parabolic curve.

So, $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

Taking the integral of the time interval in order to determine the distance; we have:

distance = $\int\limits^{3.519}_{1.866} {V_Q(t)} \, dt$

= $\int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt$

= By using the Scientific calculator notation;

distance = 106.109 m

4 0

3 years ago

10.55 = as a simplest form

Katarina [22]

Answer:

10 11/20

as a fraction.

Step-by-step explanation:

.55 is 55/100 but can be simplified. 55 and 100 can be divided by 5 so it goes to 11 and 20

5 0

3 years ago

Neeeeeeeeeeeeeeeeed heeeeeeeeeeeeeeeeelp!!!!!!!!!!!!!!!!!!!!!!!!

iren [92.7K]

Answer: -6r + 6

Hope this helps :)

4 0

3 years ago

Read 2 more answers