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3 years ago

7

Fifteen new students are to be evenly distributed among three classes. Suppose that there are three whiz-kids among the fifteen.

(a) What is the probability that each class gets one? (b) one class gets them all?

1 answer:

dimaraw [331]3 years ago

5 0

Well 3 times what equals 15 it' 5 so the probability of it will be 5 if that makes sense

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The domain of the following relation: R: {(−3, 4), (5, 0), (1, 5), (2, 8), (5, 10)} is:

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2 years ago

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Answer:

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Step-by-step explanation:

The given rational expression is:

$\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}$

We can use concept of Partial Fractions to solve this problem. Let,

$\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}$

Multiplying both sides by (x - 1)(x - 5), we get:

$3x+4=A(x-5)+B(x-1)$

Substituting x = 5, we get:

$3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}$

Substituting x = 1, we get:

$3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}$

Substituting the value of A and B, back in the original equation, we get:

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