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Lostsunrise [7]
3 years ago
15

Need help asap!! will mark brainliest

Mathematics
1 answer:
irakobra [83]3 years ago
3 0

Answer: C :D

Step-by-step explanation:

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When a ball is dropped from a state of rest at time t=0t=0, the distance, measured in feet, that it has traveled after tt second
Maru [420]

Part A. To solve for the distance travelled during the interval, all we have to do is to plug in values of t = 3 and t = 3.5 in the equation and the difference would be the answer:

when t = 3: s = 16 (3)^2 = 144 m

when t = 3.5: s = 16 (3.5)^2 = 196 m

Therefore the distance travelled within the interval is:

196 m – 144 m = 52 m

 

<span>Part B. The velocity is calculated by taking the 1st derivative of the equation. v = ds / dt</span>

s = 16 t^2

ds / dt = 32 t = v

when t = 3: v = 32 (3) = 96 m / s

when t = 3.5: v = 32 (3.5) = 112 m / s

Therefore the average velocity is:

(96 + 112) /2 = 104 m / s

 

Part C. We can still use the formula v = 32 t and plug in the value of t = 3

v = 32 t = 32 (3)

v = 96 m / s

<span>                </span>

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3 years ago
What is the surface area of the cylinder with height 4 m and radius 2 m? Round your answer to the nearest thousandth. ​
Tems11 [23]

Answer:

<h2>          75.398 m²</h2>

Step-by-step explanation:

A=2\cdot\pi R^2+ 2\pi R\cdot H\\\\H=4\,m\\R=2\,m\\\\A=2\cdot\pi\cdot 2^2+2\pi \cdot2\cdot4=8\pi+16\pi=24\pi=75.398223....\approx75.398\ m^2

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Can someone please help me with this?
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