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Schach [20]
2 years ago
13

Math again help please!!

Mathematics
1 answer:
katrin [286]2 years ago
3 0
I would say they would need to be replaced at separate times. If the tires diameter is greater then the other can travel double the distance without needing to be changed. Thats what i think
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Help with #5 please
slega [8]

729. multiple 9 times 9 then 81 times 9 and you get D

7 0
3 years ago
If f(x)=1/x+2/x, then f(1/3)=
Kaylis [27]

Answer:

f(1/3) = 9

Step-by-step explanation:

f(x)=1/x+2/x

Combine terms

f(x) = 3/x

f(1/3) = 3 / (1/3)

f(1/3) = 9

7 0
3 years ago
What is the unit rate for 108 diapers for 25.18 dollars
Alenkasestr [34]
<span><span>1.       </span>Question: Find the Unit rate for 108 diapers for 25.18 dollars.
Let’s analyze the given question. In a total of 108 diapers for 25.18 dollars.
Thus we need to find the amount of every 1 diaper then.
=> 108 diapers – is the total number of items
=> 25.18 dollars -  the total amount paid
=> Since we are looking for the price of each diapers, we need to divide the amount with the number of diapers.
=> 25.18 / 108 = 0.23 dollars.
Thus the unit rate is 0.23 dollars/ diaper</span>



4 0
3 years ago
One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p
scZoUnD [109]

Answer:

c^2 = 9dp

Step-by-step explanation:

Given

dx^2 + cx + p = 0

Let the roots be \alpha and \beta

So:

\alpha = 2\beta

Required

Determine the relationship between d, c and p

dx^2 + cx + p = 0

Divide through by d

\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0

x^2 + \frac{c}{d}x + \frac{p}{d} = 0

A quadratic equation has the form:

x^2 - (\alpha + \beta)x + \alpha \beta = 0

So:

x^2 - (2\beta+ \beta)x + \beta*\beta = 0

x^2 - (3\beta)x + \beta^2 = 0

So, we have:

\frac{c}{d} = -3\beta -- (1)

and

\frac{p}{d} = \beta^2 -- (2)

Make \beta the subject in (1)

\frac{c}{d} = -3\beta

\beta = -\frac{c}{3d}

Substitute \beta = -\frac{c}{3d} in (2)

\frac{p}{d} = (-\frac{c}{3d})^2

\frac{p}{d} = \frac{c^2}{9d^2}

Multiply both sides by d

d * \frac{p}{d} = \frac{c^2}{9d^2}*d

p = \frac{c^2}{9d}

Cross Multiply

9dp = c^2

or

c^2 = 9dp

Hence, the relationship between d, c and p is: c^2 = 9dp

8 0
3 years ago
HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!
Marrrta [24]

Answer:

For 10 plot a point 3 lines back and 5 lines back

For 11 its 2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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