let x be the first number,
so, the next two are (x+ 1) and (x+2)
x + 2(x +1) = 62 - 3(x + 2)
x + 2x + 2 = 62 -3x - 6
3x + 2 = 62 - 3x - 6
3x + 3x = 62 - 6 - 2
6x = 54
x = 9
so, three consecutive integers are
9, 10, 11
Hope this helps!
Multiply bottom equation by -3 to add and eliminate y’s.
So...
5x-15y=10
+-9x+15y=18
You get -4x=28 so x=-7
Plug in to get y
5(-7)-15y=10
-35-15y=10
-15y=45
So y=-3
Check in other equation
3(-7)-5(-3)=
-21+15=-6
So x= -7 and y= -3
Answer:
m = -1
Step-by-step explanation:
3(m + 2) = -( 6- m) + 10
Distribute
3m +6 = -6+m +10
Combine like terms
3m+6 = m+4
Subtract m from each side
3m-m+6 = m+4-m
2m+6 = 4
Subtract 6 from each side
2m+6-6 = 4-6
2m = -2
Divide by 2
2m/2 = -2/2
m = -1
Answer:
Step-by-step explanation:
-0.75g ≤ 7 - 10
-0.75g ≤ -3
g ≥ 4