Maybe it can be 3+8=11÷2=1 remainder 1 and the population encresed once
Answer:
![\large\boxed{x^2+y^2+4x-2y+1=0}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bx%5E2%2By%5E2%2B4x-2y%2B1%3D0%7D)
Step-by-step explanation:
The standard form of an equation of a circle:
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
(h, k) - center
r - radius
The general form of an equation of a circle:
![x^2+y^2+Dx+Ey+F=0](https://tex.z-dn.net/?f=x%5E2%2By%5E2%2BDx%2BEy%2BF%3D0)
We have the center (-2, 1). Substitute to the equation in the standard form:
![(x-(-2))^2+(y-1)^2=r^2\\\\(x+2)^2+(y-1)^2=r^2](https://tex.z-dn.net/?f=%28x-%28-2%29%29%5E2%2B%28y-1%29%5E2%3Dr%5E2%5C%5C%5C%5C%28x%2B2%29%5E2%2B%28y-1%29%5E2%3Dr%5E2)
Put thr coordinates of the point (-4, 1) to the equation and calculate a radius:
![(-4+2)^2+(1-1)^2=r^2\\\\r^2=(-2)^2+0^2\\\\r^2=4](https://tex.z-dn.net/?f=%28-4%2B2%29%5E2%2B%281-1%29%5E2%3Dr%5E2%5C%5C%5C%5Cr%5E2%3D%28-2%29%5E2%2B0%5E2%5C%5C%5C%5Cr%5E2%3D4)
Therefore we have the equation:
![(x+2)^2+(y-1)^2=4](https://tex.z-dn.net/?f=%28x%2B2%29%5E2%2B%28y-1%29%5E2%3D4)
Convert to the general form.
Use ![(a\pm b)^2=a^2\pm 2ab+b^2](https://tex.z-dn.net/?f=%28a%5Cpm%20b%29%5E2%3Da%5E2%5Cpm%202ab%2Bb%5E2)
![(x+2)^2+(y-1)^2=4\\\\x^2+2(x)(2)+2^2+y^2-2(y)(1)+1^2=4\\\\x^2+4x+4+y^2-2y+1=4\qquad\text{subtract 4 from both sides}\\\\x^2+y^2+4x-2y+1=0](https://tex.z-dn.net/?f=%28x%2B2%29%5E2%2B%28y-1%29%5E2%3D4%5C%5C%5C%5Cx%5E2%2B2%28x%29%282%29%2B2%5E2%2By%5E2-2%28y%29%281%29%2B1%5E2%3D4%5C%5C%5C%5Cx%5E2%2B4x%2B4%2By%5E2-2y%2B1%3D4%5Cqquad%5Ctext%7Bsubtract%204%20from%20both%20sides%7D%5C%5C%5C%5Cx%5E2%2By%5E2%2B4x-2y%2B1%3D0)
Um i dont no that one sorry
XY = 17.
Because YW is a perpendicular bisector, we can say that TW and WZ are both equal to 3. It tells us that XZ is 12, so that means that XW must be 12+3 which equals 15.
It also tells us that YW is 8. So we can use the Pythagorean Theorem to find the hypotenuse of Triangle XWY. Thus,
![15^{2} + 8^{2} = XY^{2}](https://tex.z-dn.net/?f=%2015%5E%7B2%7D%20%20%2B%20%208%5E%7B2%7D%20%3D%20%20XY%5E%7B2%7D%20)
To solve this equation, square and add both of the terms on the right like this:
![289 = XY^{2}](https://tex.z-dn.net/?f=289%20%3D%20%20XY%5E%7B2%7D%20)
And then take the square root of both sides. Your final answer should be:
XY = 17.