The height of broken part of tree from ground is 5.569m.
Justification:
Let BD is a tree of height 12 m.
<u>Suppose it got bent at a point C and let the part CD take the position CA, meeting the ground at A</u>.
i.e., CD = AC = h m
<u>Broken part makes 60° angle from ground</u>
So, ∠BAC = 60°
<u>Now, height of remaining part of tree</u> = (12 – h)m.
In right angled ∆ABC,
sin 60° = BC/AC
⇒ √3/2 = (12 - h)/h
⇒ √3h = 2(12 – h)
⇒ √3h = 24 – 2h
⇒ √3h + 2h = 24
⇒ h(√3 + 2) = 24
⇒ h(1.732 + 2) = 24
⇒ h(3.732) = 24
⇒ h = 24/3.732 = 6.4308 m
<u>Hence, height of broken tree from ground</u>
⇒ BC = 12 – h
⇒ 12 – 6.4308 = 5.569m
<u>Hence, tree is broken 5.569 m from ground</u>.
<u>Note</u>: See attached picture.
Add 12 to 16 on the other side to make 4x = 28. Then divide 28 by 4, which equals 7. Solution is x = 7
Answer:
Ben needs to get a 99% on his second test
Step-by-step explanation:
The average is the sum of both test scores, divided by the total number of test scores (2).
Let x by the grade Ben must receive on his second test.
(89 + x)/2 = 94
Multiply by 2 on both sides
89 + x = 188
Subtract 89 on both sides
x = 99
Check work:
(89 + 99)/2 = 188/2 = 99
Thanks so sorry to bother y’all yesterday but we are doing well and we are going out tomorrow morning to get our stuff done for tomorrow evening thanks for the call and I let him go to work tomorrow or tomorrow morning I can meet with him and meet him and there are we going out tomorrow at 7pm is that we can do that and if so I will let ya guys out tomorrow and I
