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trasher [3.6K]
2 years ago
5

The distance, y, in centimeters, of an ant from a hole in the tree for a certain amount of time, x, in seconds, is shown in the

graph:
Part A: Is the graph linear or nonlinear? Explain your answer. (2 points)
Part B: In which segments is the graph increasing, decreasing, and constant? (3 points)
Part C: In your own words, describe the motion of the ant, as shown on the graph. (5 points)

Mathematics
1 answer:
Alenkasestr [34]2 years ago
4 0

Answer:

<h3>Part A</h3>

The graph is non-linear as it is not a continuous straight line (with only one slope).

<h3>Part B</h3>

<u>Increasing</u>:  the y-value increases as the x-value increases

<u>Constant</u>:  the y-value stays the same as the x-value changes

<u>Decreasing</u>:  the y-value decreases as the x-value increases

Therefore,

  • Increasing segment:  Between 0 and 2 seconds
  • Constant segment: Between 2 and 3 seconds
  • Decreasing segment: Between 3 and 5 seconds

<h3>Part C</h3>

For the first 2 seconds, the ant moves 6 cm from a hole in the tree at a steady speed of 3 cm per second. For the next second, the ant is at rest then turns around. For the next 2 seconds, the ant moves 6 cm back to the hole at a steady speed of 3 cm per second.  The ant then stops.

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Vladimir79 [104]

Answer:

0.025 is the standard error of mean.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 100

Sample mean = 13 psi

Population standard deviation = 0.25 psi

We have to find the standard error of the mean.

Formula:

Standard error =

\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.25}{\sqrt{100}} = \dfrac{0.25}{10} = 0.025

0.025 is the standard error of mean.

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Alexxx [7]
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3 years ago
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Let X=[10 -3] and y=[-1 -5] then the distance between X and y is​
slavikrds [6]

Answer:

[11 2]

Step-by-step explanation:

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3 years ago
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"A laboratory tested 73 chicken eggs and found that the mean amount of cholesterol was 230 milligrams with LaTeX: \sigmaσ = 17.4
Scrat [10]

Answer:

The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96*\frac{17.4}{\sqrt{73}} = 3.99

The lower end of the interval is the sample mean subtracted by M. So it is 230 - 3.99 = 226.01

The upper end of the interval is the sample mean added to M. So it is 230 + 3.99 = 233.99.

The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.

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3 years ago
Decimal equivalent of 143%
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Answer:

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Step-by-step explanation:

%143 = 1.43

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2 years ago
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