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trasher [3.6K]
1 year ago
5

The distance, y, in centimeters, of an ant from a hole in the tree for a certain amount of time, x, in seconds, is shown in the

graph:
Part A: Is the graph linear or nonlinear? Explain your answer. (2 points)
Part B: In which segments is the graph increasing, decreasing, and constant? (3 points)
Part C: In your own words, describe the motion of the ant, as shown on the graph. (5 points)

Mathematics
1 answer:
Alenkasestr [34]1 year ago
4 0

Answer:

<h3>Part A</h3>

The graph is non-linear as it is not a continuous straight line (with only one slope).

<h3>Part B</h3>

<u>Increasing</u>:  the y-value increases as the x-value increases

<u>Constant</u>:  the y-value stays the same as the x-value changes

<u>Decreasing</u>:  the y-value decreases as the x-value increases

Therefore,

  • Increasing segment:  Between 0 and 2 seconds
  • Constant segment: Between 2 and 3 seconds
  • Decreasing segment: Between 3 and 5 seconds

<h3>Part C</h3>

For the first 2 seconds, the ant moves 6 cm from a hole in the tree at a steady speed of 3 cm per second. For the next second, the ant is at rest then turns around. For the next 2 seconds, the ant moves 6 cm back to the hole at a steady speed of 3 cm per second.  The ant then stops.

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The answer is: The diameter is 4 centimeters.

The explanation  is shown below:

1. The volume of the cylinder is:

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Then:

Vc=(8cm)^{2}}(2cm)\pi\\Vc=128\pi

2. The total volume of the 12 spheres is:

Vs=12(\frac{4}{3}r^{3}\pi)\\Vs=16r^{3}\pi

3. The volume of the cylinder and the total volume of all the 12 spheres, are equal, therefore:

Vc=Vs\\128\pi=16r^{3}\pi

4. Now, you must solve for the radius:

r=\sqrt[3]{\frac{128\pi}{16\pi}}\\r=2cm

5. The diameter is:

d=2r\\d=2(2cm)\\d=4cm

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The radius of circle A is r cm. The radius of circle B is twice the radius of circle A. What difference between the circumferenc
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Answer:

  2πr cm

Step-by-step explanation:

The circumference of a circle of radius r is ...

  C = 2πr

For a radius of (r cm), the circumference is ...

  A = 2π(r cm) = 2πr cm

For a radius of (2r cm), the circumference is ...

  B = 2π(2r cm) = 4πr cm

Then the difference between the circumferences is ...

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A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
WITCHER [35]

Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

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