1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alenkinab [10]
3 years ago
14

PLEASE HELP!!! I will give brainliest answer!!! Find the volume and surface area of these.

Mathematics
1 answer:
k0ka [10]3 years ago
4 0

Answer:

(I only have the answers for 3 and 4) 3. Volume: 192 Surface Area: 16 4. Volume: 1,200 Surface Area: 100

Step-by-step explanation:

3. Volume: 4 x 4 = 16 x 12 = 192 Surface Area: 4 x 4 = 16 4. Volume: 10 x 10 = 100 x 12 = 1,200 Surface Area: 10 x 10 = 100

You might be interested in
Solve any method: 9x^2+9x=4??
Gala2k [10]
Subtract 4 from both sides, solve using quadratic formula
ax^2+bx+c
(-b(+or-) Square Root of b^2 - 4ac)/2a

9x^2+9x-4=0
-9(+or-)Square root of 9^2-4(9)(-4)/2(9)

Solve^
6 0
3 years ago
Read 2 more answers
How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
3 years ago
Solve for x
Mademuasel [1]

Answer:

x = 9

Step-by-step explanation:

Using the rule of exponents

a^{m} × a^{n} ⇔ a^{(m+n)}

Given

11^{x} = 11^{4} × 11^{5} = 11^{(4+5)} = 11^{9}

Since the bases on both sides are common, then equate the exponents

x = 9

4 0
2 years ago
15. A 3 kg ball is thrown upward with a velocity of 10 m/s.
11Alexandr11 [23.1K]
The answer is A- between 8 m& 12m
5 0
3 years ago
Mrs. Garcia used 5 cups of flour to make 3 loaves of bread. How many loaves of bread can she make with 30 cups of flour?
pochemuha
Well first you would do 5 / 30 which makes 6 then you would 6 times 3 equals 18. So she would make 18 loaves of bread. 
3 0
3 years ago
Other questions:
  • How to find components of a vector given magnitude and angle?
    15·1 answer
  • What are the steps for adding and subtracting mixed numbers with unlike denominators
    10·2 answers
  • Department s had 500 units 60% completed in process at the beginning of the period; 9,000 units completed during the period; and
    6·1 answer
  • How do u get 55 from 3 7 12 2
    10·1 answer
  • Is -1 1/2 rational?
    9·2 answers
  • Esmeralda bought 12.22 worth of 43 cent stamps and 81 cent stamps. The number of 81 cent stamps was 14 less than the number of 4
    13·1 answer
  • 1+4=5 2+5=12 3+6=21 8+11=
    5·1 answer
  • What type of triangle ALWAYS has three equal sides?
    6·2 answers
  • Due for 10:00am need help​
    9·1 answer
  • A bank is offering 2.5% simple interest on a savings account. If Jayden deposits $5000,
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!