If it is 1/2 a foot long, there will be 4 1/8ft sections.
Answer:
Given: A triangle ABC and a line DE parallel to BC.
To prove: A line parallel to one side of a triangle divides the other two sides proportionally.
Proof: Consider ΔABC and DE be the line parallel to Bc, then from ΔABC and ΔADE, we have
∠A=∠A (Common)
∠ADE=∠ABC (Corresponding angles)
Thus, by AA similarity, ΔABC is similar to ΔADE, therefore
AB/AD= AC/AE
⇒AD+DB/AD = AE+EC/AE
⇒1+DB/AD = 1+ EC/AE
⇒DB/AD = EC/AE
Therefore, a line parallel to one side of a triangle divides the other two sides proportionally.
⇒Therefore Proved
Hope this helps!!!
Answer: F
Step-by-step explanation:
- This does not have infinitely many solutions (adding the equations, we get a fixed value of x)
- This has no solutions (the left hand sides are the same but the right hand sides have different values)
- This has one solution (the first equation givess a fixed value for x)
- This has no solutions (same reason as 2)
- This has one solution (same reason as 3, just the second equation instead of the first)
- This has infinitely many solutions (multiplying both sides of the top equation by -2 gives the bottom equation).
Answer:
apparently just label each part ( a, b, c, d, so on) and tell the order/ switch em around
Step-by-step explanation:
Answer:
Sandy did not follow PEMDAS and added first instead of doing her multiplication and division and then her addition and subtraction the answer would be 18
