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3 years ago

Find tan if sin=1/4 and falls in Quadrant 1

1 answer:

7 0

Ok, sin = prep / hyp

so, perpendicular = 1 , and hypo = 4
so, base = sq. root ( 16-1 ) = root 15

and tan = prep / base = 1 / root (15)

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A school gym is divided for a fair by bisecting its width and its length. Each half of the length is then bisected, forming 8 s

SVETLANKA909090 [29]

Answer:

Dimensions will be

New Length= x/16 units

New width = y/2 units

Area=xy/32 square units

Step-by-step explanation:

Lets assume the dimensions of the school gym to be ;

Length= x

width= y

Length and width are first bisected for a fair.This means by a half

Length will be =x/2

Width will be =y/2

Then the length is divided to form 8 sections that are equal, which will ;

(x/2)÷8

x/2 * 1/8 = x/16 units

New length = x/16 units in dimension

New width will be y/2 units in dimension

Area of each section will be;

length by width

(x/16 )*(y/2)

=xy/32 square units

7 0

3 years ago

Read 2 more answers

How do I solve this question?

olya-2409 [2.1K]

Hello,

we can simplify as below

$\dfrac{(2p^3q^4)^4}{(-3q^5)^2}*\dfrac{9}{(4p^2q)^2}=\dfrac{2^4p^{12}q^{16}3^2}{3^2q^{10}4^2p^4q^2}=p^{12-4}q^{16-10-2}=p^{8}q^{4}=p^{a+b}q^{b-a}$

So it means that

8 = a+b

4 = b-a

8+4 = a+b+b-a=2b

2b = 12

b = 6

and a = 6 - 4 = 2

hope this helps

7 0

3 years ago

Point R is located at (3, 2) and point S is located at (8, 15) . What are the coordinates of the point that partitions the direc

Sliva [168]

Hello There!

The coordinates would be (17/4, 21/4)

Hope This Helps You!
Good Luck :)

- Hannah ❤

5 0

4 years ago

VWhat number is in the tenths place in the number 1234.765

iren [92.7K]

Answer:

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Simplify the expression and find its value when a = 5 and b = -3 .

kenny6666 [7]

Answer:

$\sf\longmapsto \: 38$

Step by step explanation:

$\sf\longmapsto \: 2a² + 2ab +3-ab$

$\sf\longmapsto \: 2a² + 3 + ab (2-1)$

$\sf\longmapsto \: 2a² + 3 + ab (1)$

$\sf\longmapsto \: 2a² + 3 + ab$

$\sf\longmapsto \: 2a² + ab + 3$

Putting a = 5 b = - 3

$\sf\longmapsto \: 2(5) {}^{2} + (5) (-3) +3$

$\sf\longmapsto \: 2 (25) - 15 + 3$

$\sf\longmapsto \: 50 - 12$

$\sf\longmapsto \: 38$

7 0

3 years ago

Read 2 more answers