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777dan777 [17]
3 years ago
12

Mario builds a triangular table to fit in the corner of his rectangular bedroom. Is it possible to construct more than one table

with angles that measure 45°, 90°, and 45°? Use the drop-down menus to explain your answer. It possible because the tables could have angle measures and side lengths.
Mathematics
1 answer:
Viefleur [7K]3 years ago
4 0

Answer 1 with Explanation

Obtained from the question, Mario builds a triangular table to fit in a corner of the bedroom with the construction measure of 45,90 and 45 degrees which will be possible. In order to construct any physical object, proper tool are needed for accuracy of the object to built more than one of the similar table. With the help of proper instruments and measurement Mario can easily make a triangular table for his room's corner.

Answer 2 with Explanation

As Mario built the triangular table for the corner to fit his bedroom corner. He make use of the special instrument and tool for the measurement. Indeed, it is possible to construct more than one table with the angles 45,45,90 as each of them will be similar in shape but with different values of x, hence it will differ in sizes in terms of length. The length will differ as per the requirement of Mario's needs.

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The area of a rectangular garden can be expressed as A = 2x^2 -x -6. The width of the garden is 2x+3. Find an expression for the
zalisa [80]

Answer:

Step-by-step explanation:

2x² -x - 6 = 2x² - 4x + 3x - 3*2

              = 2x*(x - 2) + 3*(x - 2)

              = (x-2)(2x + 3)

A = 2x² -x - 6

A = (x - 2)(2x + 3)

length*width = (x - 2)(2x + 3)

length * (2x +3) = (x - 2)(2x + 3)

length=\frac{(x-2)(2x+3)}{(2x+3)}

length = x - 2

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3 years ago
What’s the equation ? (2,-2) ( 4,1)
oksano4ka [1.4K]

Answer:

y = 3 2x − 5

Step-by-step explanation:

5 0
3 years ago
Given the following function ,find h(-4) <br><br>h(x)=6x^2+5​
Wittaler [7]

Answer:

h(-4) =101

Step-by-step explanation:

H(x) = 6x ^2 +5

We have  to find when h=4, putting it into function

h(-4) = 6(-4) ^2 +5

h(-4) = 6(16) +5

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3 years ago
A car insurance company has high-risk, medium-risk, and low-risk clients, who have, respectively, probabilities .04, .02, and .0
Paha777 [63]

Answer:

(a) 0.983

(b) 0.353 or 35.3%

(c) 0.604 or 60.4%

Step-by-step explanation:

a) The probability of a random client does not file a claim is equal to the sum of:

1) the probability of a client being high risk and does not file a claim = P(hr)*(1-P(c_hr))

2) the probability of a client being medium risk and does not file a claim = P(mr)*(1-P(c_mr))

and

3) the probability of a client being low risk and does not file a claim = P(lr)*(1-P(c_lr))

P(not claim) = P(hr)*(1-P(c_hr))+P(mr)*(1-P(c_mr))+P(lr)*(1-P(c_lr))

P(not claim) = 0.15*(1-0.04)+0.25*(1-0.02)+0.6*(1-0.01)

P(not claim) = 0.15*0.96+0.25*0.98+0.6*0.99 = 0.983

(b) To know the proportion of claims that come from high risk clients we need to know the total expected claims in every category:

Claims expected by high risk clients = P(c_hr)*P(hr) = 0.04*0.15 = 0.006 claims/client

Claims expected by medium risk clients = P(c_mr)*P(mr) = 0.02*0.25 = 0.005 claims/client

Claims expected by low risk clients = P(c_lr)*P(lr) = 0.01*0.60 = 0.006 claims/client

The proportion of claims done by high risk clients is

Claims by HR clients / Total claims expected = 0.006 / (0.006+0.005+0.006) =  0.006 / 0.017 = 0.3529 or 35,3%

(c)  The probability of being a client of a particular category and who don't file a claim is:

1) High risk: 0.15*(1-0.04) = 0.144

2) Medium risk: 0.25*(1-0.02) =  0.245

3) Low risk: 0.6*(1-0.01) = 0.594

The probability that a random client who didn't file a claim is low- risk can be calculated as:

Probability of being low risk and don't file a claim / Probability of not filing a claim

P(LR&not claim)/P(not claim) = 0.594 / (0.144+0.245+0.594)

P(LR&not claim)/P(not claim) = 0.594 /  0.983 = 0.604 or 60.4%

6 0
3 years ago
-1-x^4/2-3x^2<br> Please help me
Romashka [77]

Answer:

hi there!

there are three answers: x= 1.367, -1.367, and 0

Step-by-step explanation:

please refer to the graph down below

8 0
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