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2 years ago

How to estimate, then find the sum of137,638 52,091

Mathematics

1 answer:

MA_775_DIABLO [31]2 years ago

4 0

137,638 + 52,091=

189,729

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If one letter is chosen at random from the word refuse what is the probability that the letter chosen will be an e

mrs_skeptik [129]

Answer: 1/3

Step-by-step explanation: The probability is given by the number of times the event could happen (in this case get an "e"), over the number of all the possibilities (in this case, the six letters of the word)

Therefore, probability $\frac{letter_e}{all letter}=\frac{2}{6} =\frac{1}{3}$

5 0

2 years ago

Need help with this one!!!

DaniilM [7]

$\bf (2x^2)^4(5x^6)\impliedby \textit{distributing the exponent}
\\\\\\
2^4x^{2\cdot 4}5x^6\implies 2^4\cdot 5x^{2\cdot 4}x^6\implies 16\cdot 5x^8x^6\implies 80x^{8+6}
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80x^{14}$

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3 years ago

At the beginning of the week the balance in your checkbook was $298.72. During the week you made a deposit of $425.69. You also

Furkat [3]

Hello!

Throughout this problem, we will add or subtract values from our original balance.

In your checkbook, there was 298.72 dollars, and then you deposited 425.69 dollars. The function you would do is addition.

$298.72 + 425.69 = $724.41

If you wrote a check, then the amount you wrote is removed from your checkbook.

$724.41 - $29.72 - $135.47- $208.28 = $350.94

Then, the bank deducted 5 dollars from your account.

$350.94 - $5.00 = $345.94

This leaves you with $345.94 at the end of the week.

Therefore, your answer is choice C, $345.94.

4 0

2 years ago

Read 2 more answers

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

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2 years ago

Properties of Light Lab Report

lakkis [162]

Answer:

Can You Give Me Some More Information

Step-by-step explanation:

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1 year ago