So most likely what this equation would end up being would be 2x + 17x added together t make 19x + 16 = 0
Hpe I helped =)
Answer:
31 L
Step-by-step explanation:
Here is the complete question
An ambulance require diesel as fuel because of so many trips nearby pump purchase diesel in bulk for the ambulance there are three containers at the pump which contain 403 L 434 L and 465 L of diesel respectively the maximum capacity of measuring container that can be measured the diesel of the three containers an exact number of times is
Solution
To find the exact number of times in which we can measure the diesel in the three containers, since the capacity of each container is 403 L, 434 L and 465 L respectively, we find the prime factors of each number.
The prime factors of 403 = 13 × 31
The prime factors of 434 = 2 × 7 × 31
The prime factors of 465 = 3 × 5 × 31
The measuring capacity equals the highest common factor (H.C.F) of the three numbers. That is H.C.F of 403, 434, 465.
Since it can be seen here that the H.C.F is 31, then the maximum capacity of measuring container that can be measured the diesel of the three containers an exact number of times is 31 L
Answer:
20 times an hour so 20 times 48 is 960 1920-960 is 960 gallons so there is 960 gallons of water left
Answer:
radius = 30 in
Step-by-step explanation:
EF = circumference × fraction of circle, substitute values
5π = 2πr × 
← where r is the radius
5π = 2πr × 
Multiply both sides by 12 to clear the fraction
60π = 2πr ( divide both sides by 2π )
= r, thus
r = 30 in
Answer:
I believe your answer is A.
Step-by-step explanation:
2x2x2
2x2=4
4x2=8
Therefore, x=2.
