Answer:
angle 1
Step-by-step explanation:
Answer:
<u>Alternative hypothesis 1</u>: the mean amperage at which the fuses burn out is > 40 amperes.
<u>Alternative hypothesis 2</u>: the mean amperage at which the fuses burn out is < 40 amperes.
Step-by-step explanation:
Recall that the null hypothesis is the fact you want to refute and is in doubt.
So, in this specific case, <em>the null hypothesis would be that the mean amperage at which the fuses burn out is 40 amperes.
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The alternative hypothesis are those that want to refute the null hypothesis, in this case there are 2:
<u>Alternative hypothesis 1:</u> the mean amperage at which the fuses burn out is > 40 amperes.
<u>Alternative hypothesis 2:</u> the mean amperage at which the fuses burn out is < 40 amperes.
A circular plot is watered by a sprinkler that rotates through it. The sprinkler only rotates through a semi-circle, or half of the whole circle.
Area of a circle: A = pi x r^2
r = 160 / 2 = 80
A = pi x 80^2
A = 6400pi / 2 = 3200pi
3200pi = 10053.0965
The area water is approximately 10,053 ft^2.
Hope this helps!! :)
Answer:
5.5
Step-by-step explanation:
2x8 = 16
3x3.5=10.5
16-10.5 = 5.5
Find the general solution by separating the variables then integrating:
dy / dx = cosx℮^(y + sinx)
dy / dx = cosx℮ʸ℮^(sinx)
℮^(-y) dy = cosx℮^(sinx) dx
∫ ℮^(-y) dy = ∫ cosx℮^(sinx) dx
-℮^(-y) = ℮^(sinx) + C
℮^(-y) = C - ℮^(sinx)
-y = ln[C - ℮^(sinx)]
y = -ln[C - ℮^(sinx)]
Find the particular solution by solving for the constant:
When x = 0, y = 0
-ln(C - 1) = 0
ln(C - 1) = 0
C - 1 = 1
C = 2
<span>y = -ln[2 - ℮^(sinx)]
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